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Which of the plots of ln K vs (1/T) is/a...

Which of the plots of ln K vs `(1/T)` is/are correct?

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
`DeltaG^(@) = -RT ln K_(eq) = DeltaH^(@) - T DeltaS^(@)`
ln `K_(eq) = (-DeltaH^(@))/R.1/T +(DeltaS^(@))/R`
Slope `=(-DeltaH^(@))/R, y1` in tercept `t=(DeltaS^(@))/R`
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Knowledge Check

  • Which is the correct plot for In k vs 1/T?

    A
    B
    C
    D

  • In the Arrhenius plot of ln k vs (1)/(T) , a linear plot is obtained with a slope of -2 xx 10^(4) K . The energy of activation of the reaction (in kJ "mole"^(-1) ) is (R value is 8.3 J K^(-1) mol^(-1) )

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    166
    C
    249
    D
    332

  • In accordance to Arrhenius equation, the plot of log k against (1)/(T) is a straight line. The slope of the line is equal to

    A
    `(-E_(a))/(R )`
    B
    `(-2.303)/(E_(a).R)`
    C
    `(-E_(a))/(2.303R)`
    D
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