The hardness of a water sample containing `10^(-3)M MgSO_(4)` expressed as `CaCO_(3)`equivalents (in ppm) is `""_____________` (Molar mass of `MgSO_(4)` is `120.37 g//mol)`

Hardness of a water sample is 100 "ppm" CaCo_(3) . Thus molarity of CaCO_(3) is

Determine the degree of hardness of a sample of water containing 30 ppm of MgSO_(4) .

Hardness of water sample is 300 ppm CaCO_3 Hence its molarity is:

the hardness of a water sample (in terms of Equivalents of CaCO_(3) ) containing 10^(-3)MCaSO_(4) Is : (Molar mass of CaSO_(4)=1365h mol^(-1) )

100 mL of a water sample contains 0.81g of calcium bicarbonate and 0.73g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalent of CaCo_3 is 10^x ppm. What is numerical value of x? (molar mass of calcium bicarbonate is 162 gmol^(-1) and magnesium bicarbonate is 146g mol^(-1))

10 g of CaCO_(3) contains :

100g of a water samples is found to contain 12 mg of MgSO_(4) calculate the hardness of water sample.