The enthaply of atomisation for the reaction : `CH_(4)(g) to C(g) + 4 H(g)` is `1665 kJ "mol"^(-1)`.What is the bond enthalpy of C-H bond? (Keep your answer in KJ/mol and three digits only)

Explanation

In `CH_(4)`, there are four `C - H` bonds. The enthalpy of atomisation of 1 mole of `CH_(4)` means dissociation of four moles of `C - H`bonds.
`:. C - H` bond energy per mol `= (1665 kJ)/(4 mol)`
`= 416.25 kJ mol^(-1)`