Home
Class 11
BIOLOGY
Roots obtain oxgyen from air soil for re...

Roots obtain oxgyen from air soil for respiration , In the absence or deficiency of `O_(2)` , root growth is restricted or completely stopped. How do the plants growing in marsh lands or swamps obtain their `O_(2)` required for root respiration ?

Text Solution

Verified by Experts

The root of the plants (e.g. Rhizophora ) growth in marshy/swamp areas become negatively geotropic . They grow vertically upwards in air, above the soil level and respire so called respiratory roots or pneumatophores .
Promotional Banner

Topper's Solved these Questions

  • MORPHOLOGY OF FLOWERING PLANTS

    NCERT EXEMPLAR|Exercise Short Answer Type Questions|14 Videos
  • MORPHOLOGY OF FLOWERING PLANTS

    NCERT EXEMPLAR|Exercise Long Answer Type Questions|8 Videos
  • MORPHOLOGY OF FLOWERING PLANTS

    NCERT EXEMPLAR|Exercise Long Answer Type Questions|8 Videos
  • MINERAL NUTRITION

    NCERT EXEMPLAR|Exercise Long Answer Type Questions|8 Videos
  • NEURAL CONTROL AND CO-ORDINATION

    NCERT EXEMPLAR|Exercise LONG ANSWER TYPE QUESTIONS|3 Videos

Similar Questions

Explore conceptually related problems

Respiration requires O_(2) . How did the first cells on the earth magage to survive in an atmosphare that lacked O_(2) ?

Statement 1: To maintain soil fertility, it is essential to prevent desertification and deforestation. Statement 2: Roots of plants grasp soil well and prevent removal of top soil by air, water, etc.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. In the previous problem, what should be the corresponding projection angle.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. A tower is at a distance of 5m from a man who can throw a stone with a maximum speed of 10m//s . What is the maximum height that the man can hit on this tower.