Home
Class 12
CHEMISTRY
Given : E(Fe^(3+)//Fe)^(@) = -0.036V, E(...

Given : `E_(Fe^(3+)//Fe)^(@) = -0.036V, E_(FE^(2+)//Fe)^(@)= -0.439V`. The value of electrode potential for the change, `Fe_(aq)^(3+) + e^(-)rightarrow Fe^(2+) (aq)` will be :

A

(-o.072V)

B

(o.385V)

C

`(0.770V)`

D

`(0.270)`

Text Solution

AI Generated Solution

To find the electrode potential for the reaction \( \text{Fe}^{3+} + e^- \rightarrow \text{Fe}^{2+} \), we can use the given standard reduction potentials for the half-reactions involving iron. ### Step-by-Step Solution: 1. **Identify the Given Standard Reduction Potentials:** - \( E^\circ(\text{Fe}^{3+}/\text{Fe}) = -0.036 \, \text{V} \) - \( E^\circ(\text{Fe}^{2+}/\text{Fe}) = -0.439 \, \text{V} \) ...
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

Consider the following E^(@) values E^(@) values E_(Fe^(3+)//Fe^(2+))^(@)= 0.77v , E_(Sn^(2+)//Sn)^(@) = -0.14 under standard condition the potential for the reaction Sn_(s)+ 2Fe^(3+)(aq)rightarrow 2Fe^(2+)(aq) + Sn^(2+) (aq) is :

Given : E_(Fe^(3+)//Fe)^@=-0.036 V E_(Fe^(2+)//Fe)^@=-0.439 V. The value of standard electrode potential for the change, Fe_((aq))^(3+)+e^(-)toFe_((aq))^(2+) will be

Knowledge Check

  • E_(M^(3+)//(M))^(@) = -0.036V , E_(M^(2+)//M)^(@)= -0.439V . The value of standard electrode potential for the change, M^(3+)(aq) + e^(-)rightarrow M^(2+) (aq) will be :

    A
    `(-0.072V)`
    B
    `(0.385V)`
    C
    `(0.770V)`
    D
    `0.270V`

  • Given E_(Cr^(3+)//Cr)^(@) = -0.72 V, E_(Fe^(2+)//Fe)^(@) = -0.439 V . The value of standard electrode potential for the change, Fe_(aq.)^(3+) + e^(-) rarr Fe_(aq.)^(2+) will be:

    A
    `-0.072 V`
    B
    `0.385 V`
    C
    `0.770 V`
    D
    `-0.270 V`

  • E_(Fe^(3+)//Fe)^(@)=-0.036V,E_(Fe^(2+)//Fe)^(@)=-0.0439V . The value of standard electrode potential for the change, Fe^(3+)(aq)+e^(-)toFe^(2+)(aq) will be

    A
    `-0.072V`
    B
    `-0.385V`
    C
    `-0.020V`
    D
    `-0.270V`

    • Similar Questions

    Explore conceptually related problems

    Given E_(Fe^(3+)//Fe)^(o)=-0.036V,E_(Fe^(2+)//Fe)^(o)=-439V the value of standard electrode potential for the change, Fe_((aq))^(3+)+e^(-)toFe^(2+)(aq) will be

    Given E_(Fe^(3+)//Fe)^(@)=-0.036V,E_(Fe^(2+)//Fe)^(@)=-0.439V . The value of E_(Fe^(3+)//Fe^(2+))^(@) will be

    Given, {:(E_(Fe^(3+) //Fe)^o + 3e E^o =- 0.036 V),(E_(Fe^(3+) //Fe)^o =- 0.439 V):} The value of standard electrode ptoential for the charge,

    The standard reduction for the following reactions are : Fe^(3+) + 3e^(-) rarr Fe with E^(@) = - 0.036 V Fe^(2+) + 2e^(-) rarr Fe with E^(@) = - 0.44 V What would be the standard electrode potential for the reaction Fe^(3+) + e^(-) rarr Fe^(2+) ?

    Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):} The standard electrode potential E^(@) for Fe^(3+) + e^(-) rarr Fe^(2+) is :

    Home
    Profile