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Reaction A+BrarrC+D follows rate law .r=...

Reaction `A+BrarrC+D` follows rate law .`r=k[A]^(1//2)[B]^(1//2)` Starting with 1 M of A and B each. What is the time taken fro concetration of A become `0.1M`?
(Given`k=2.303xx10^(-2)sec^(-1))`

A

300 sec

B

600 sec

C

900 sec

D

none of these

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Reaction A+B rarr C+D follows rate law R=K[A]^(1//2)[B]^(1//2) starting with 1 M of A and B . What is time taken for concentration of A to become 0.1 M ? [Given , k=4.606xx10^(-4)s^(-1) ]

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  • Reaction A+BtoC+D is started with 1 M of each A and B and follows the rate law r=k[A]^(1//2)[B]^(1//2) What is the time taken for the concentration of A to drop to 0.1 M (K=2.303xx10^(-3)sec^(-1))

    A
    57 sec
    B
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  • For the following reaction A(g) + B(g) rarr 2C(g) + D(g), the law is given as R = [A]^(1//3).[B]^(2//3) . If initially concentration of A and B are unity then total molar concentration of all gases at t=600 sec. will be : [Given : K=2.31xx10^(-3)sec^(-1) ]

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