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Ozone in the earth's atmosphere decompos...

Ozone in the earth's atmosphere decomposes according to the equation: `2O_(3)(g) rarr 3O_(2)(g)` This reaction is thought to occur via the two-step mechanism:
Step 1:` O_(3)(g) hArr O_(2)(g) +O(g)` Fast, reversible
Step 2: `O_(3)(g) +O(g) rarr 2O_(2)(g)` slow
What rate law is consistent with this mechanism?

A

for step I, molecularity is 2

B

for step II, molecularity is 1

C

step II is rate determining step

D

Rate law expression for the overall reaction is `-(d)/(dt) [O_(3)]=k[O_(3)]^(2)[O_(2)]^(-1)`

Text Solution

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The correct Answer is:
C, D
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Knowledge Check

  • A possible mechanism for the conversion for ozone to oxygen in the upper atmosphere is O_(3)(g) hArr O_(2)(g) +O(g) " " (fast equilibrium) O(g) +O_(3)(g) rarr 2O_(2)(g)" " (slow) Which rate law is consistent with this mechanism?

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