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Calculate the freezing point of a one-mo...

Calculate the freezing point of a one-molar aqueous solution (density 1.06 g `mL_(-1) `) of KBr. `K_"f"` for water = 1.86 K kg `mol^(-1)`. Atomic mass: K = 39, Br = 80.

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To calculate the freezing point of a one-molar aqueous solution of KBr, we will follow these steps: ### Step 1: Understand the Problem We need to find the freezing point of a 1 molar aqueous solution of KBr. The freezing point of pure water is 273.15 K, and we will use the formula for freezing point depression to find the new freezing point. ### Step 2: Identify the Required Values - **Freezing point depression constant (Kf) for water**: 1.86 K kg/mol - **Density of the solution**: 1.06 g/mL ...
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Calculate the freezing point of the one molar aqueous solution (density 1.04 g L^(-1) ) of KCl ( k_(f) for wateer = 1.86 kg mol^(-1) , atomic mass of K = 39 ,Cl = 35.5)

Calculate the boiling point of a one molar aqueous solution (density 1.04 g "mL "^(1) ) of potassium chloride K_(b) for water = 0.52 K "mol "^(-1) . Atomic masses : K = 39, Cl = 35.5 )

Knowledge Check

  • What should be the freezing point of aqueous solution containing 17g of C_(2)H(5)OH is 1000g of water ( K_(f) for water = 1.86 deg kg mol^(-1) )?

    A
    `-0.69^(@)C`
    B
    `0.34^(@)C`
    C
    `0.0^(@)C`
    D
    `-0.34^(@)C`

  • What would be the freezing point of aqueous solution containing 17 g of C_(2)H_(5)OH in 100 g of water (K_(f) H_(2)O = 1.86 K mol^(-1)kg) :

    A
    `-6.8^(@)C`
    B
    `-0.34^(@)C`
    C
    `0.0^(@)C`
    D
    `0.34^(@)C`

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    Calculate the freezing point of a containing 60g of glucose (Molar mass= 180 g mol^-1 ) in 250g of water (K_l of water =1.86 K kg mol^-1 )

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