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The molarity of 20% (W/W) solution of su...

The molarity of 20% (W/W) solution of sulphuric acid is 2.55 M. The density of the solution is :

A

1.25 g `cm^(-3)`

B

0.125 g `L^(-1)`

C

2.25 g `cm^(-3)`

D

unpredictable

Text Solution

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The correct Answer is:
To find the density of a 20% (W/W) solution of sulfuric acid given that its molarity is 2.55 M, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information:** - Molarity (M) = 2.55 M - Weight/Weight percentage (W/W) = 20% - Assume the weight of the solution = 100 g for simplicity. 2. **Calculate the Weight of the Solute:** - Since it is a 20% (W/W) solution, the weight of the solute (H₂SO₄) in 100 g of solution is: \[ \text{Weight of solute} = 20\% \text{ of } 100 \text{ g} = 20 \text{ g} \] 3. **Calculate the Molar Mass of Sulfuric Acid (H₂SO₄):** - The molar mass of H₂SO₄ is calculated as follows: - Hydrogen (H) = 1 g/mol × 2 = 2 g/mol - Sulfur (S) = 32 g/mol × 1 = 32 g/mol - Oxygen (O) = 16 g/mol × 4 = 64 g/mol - Total = 2 + 32 + 64 = 98 g/mol 4. **Calculate the Number of Moles of Solute:** - Using the weight of the solute and its molar mass, the number of moles of H₂SO₄ can be calculated: \[ \text{Number of moles} = \frac{\text{Weight of solute}}{\text{Molar mass}} = \frac{20 \text{ g}}{98 \text{ g/mol}} \approx 0.2041 \text{ moles} \] 5. **Calculate the Volume of the Solution:** - Molarity is defined as the number of moles of solute per liter of solution. Rearranging the formula gives: \[ \text{Volume of solution (L)} = \frac{\text{Number of moles}}{\text{Molarity}} = \frac{0.2041 \text{ moles}}{2.55 \text{ M}} \approx 0.0800 \text{ L} \] - Converting liters to milliliters: \[ \text{Volume of solution (mL)} = 0.0800 \text{ L} \times 1000 \text{ mL/L} = 80.0 \text{ mL} \] 6. **Calculate the Density of the Solution:** - Density is defined as mass per unit volume. Therefore: \[ \text{Density} = \frac{\text{Weight of solution}}{\text{Volume of solution}} = \frac{100 \text{ g}}{80.0 \text{ mL}} = 1.25 \text{ g/mL} \] ### Final Answer: The density of the 20% (W/W) solution of sulfuric acid is **1.25 g/mL**.

To find the density of a 20% (W/W) solution of sulfuric acid given that its molarity is 2.55 M, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information:** - Molarity (M) = 2.55 M - Weight/Weight percentage (W/W) = 20% - Assume the weight of the solution = 100 g for simplicity. ...
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Knowledge Check

  • Molarity of 4% (w/v) solution of NaOH is

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    `0.1`
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