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Consider the following cell with hydroge...

Consider the following cell with hydrogen electrodes at difference pressure `p_(1)` and `p_(2)`.

The `EMF` of the cell is given by

A

`(RT)/F log_e (p_1/p_2)`

B

`(RT)/(2F) log_e (p_1/p_2)`

C

`(RT)/(F) log_e (p_2/p_1)`

D

`(RT)/(2F) log_e (p_2/p_1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • Emf of hydrogen electrode (at 1 atm pressure) in term of pH is

    A
    `E_(H_(2))=(RT)/(F) xx pH`
    B
    `E_(H_(2))=(RT)/(F) 1/(pH)`
    C
    `E_(H_(2))=(2.303RT)/(F) pH`
    D
    `E_(H_(2))=0.0591pH`

  • The emf of a cell is the ratio of the difference in

    A
    charge in coulombs to the electrical potential energy in joules
    B
    electrical potential energy in joules to the charge in coulombs
    C
    electrical potential energy in joules to the resistance
    D
    electrical potential energy in joules to the time

  • EMF of hydrogen electrode in terms of pH is (at 1 atm pressure)

    A
    `E_(H_(2)=(RT)/(F)xxpH`
    B
    `E_(H_(2))=(RT)/(F)=(1)/(pH)`
    C
    `E_(H_(2))=(2.303 RT)/(F)pH`
    D
    `E_(H_(2))=-0.591 pH`

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