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How many chlorine atoms will be ionised ...

How many chlorine atoms will be ionised `Cl to Cl^(-) + e^(-)` by the energy released from the process `Cl + e^(-) to Cl^(-)` for `6.02 xx 10^(23)` atoms (I.P for Cl = 1250 kJ `mol^(-1)` and E.A. = `350 kJ "mole"^(-1)`)

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To solve the question of how many chlorine atoms will be ionized by the energy released from the process of gaining an electron, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Processes Involved**: - The ionization process of chlorine can be represented as: \[ \text{Cl} \rightarrow \text{Cl}^+ + e^- ...
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How many chlorine atoms will be ionised CI rarr CI^(+) +e^(-1) by the energy released from the process CI +e^(-1) rarr CI^(-) for 6.02 xx 10^(23) atoms (I.P. for CI = 1250 kJ mol^(-1) and E.A. = 350 kJ "mole"^(-1))

How many echlorine atoms can ionize in the process: Cl to Cl^(+) + e , by the energy liberated from the following process. Cl + e to Cl^(-) for 6 xx 10^(23) atoms Given electron affinity of Cl = 3.61ev and Ionization potential fo Cl = 17.422 ev .

Knowledge Check

  • How many chlorine atoms can you ionize in the process Cl rarr Cl^+ + e , by the energy liberated from the following process ? Cl + e^- rarr Cl^(-) for 6 xx 10^23 "atoms" Given electron affinity ofm Cl = 3.61 eV , and I P of Cl = 17.422 eV .

    A
    `1.24 xx 10^23 "atoms"`
    B
    `9.82 xx 10^20 "atoms"`
    C
    `2.02 xx 10^15 "atoms"`
    D
    none of these

  • The number of atoms you can ionise in the process Cl rarr Cl^(+)+ e^(-) by the energy liberated for the process Cl+e^(-) rarr Cl^(-) for the avagadro number of atoms (" given " IE=13eV , EA=3.6eV)

    A
    `1.667 X 10^(23)`
    B
    `3.3 X 10^(23)`
    C
    `6.023 X 10^(22)`
    D
    `1.505 X 10^(22)`

  • In the process , Cl(g) + e^(-) overset(DeltaH)(to)Cl^(-)(g) , DeltaH is

    A
    positive
    B
    negative
    C
    zero
    D
    unpredictable

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    How many Cl atosm can you ionise in the process Cl rarr Cl^+ + e, by the energy liberated for the process Cl + e rarr rarr Cl^- for one Avogadro's number of atoms ? (Given : IP = 13. 0 eV and EA = 3.60 eV ) .

    The amount of energy released when 10^(12) atoms of Cl vapours are converted to Cl^(ɵ) ions, according to the equation : C_((g))+e^(-) rarr Cl_((g))^(ɵ) is 58 xx 10^(-10)J Calculate the Delta_(eg)H^(ɵ) of Cl atom in kJ mol^(-1) and eV "atom"^(-1) .

    In the process Cl _((g)) + e overset( Delta H) to Cl ^(-) _((g) Delta H is

    What will be DeltaH for the reaction, CH_(2)Cl_(2)rarrC+2H+2Cl ? (B.E. of C-H and C-Cl bonds are "416 kJ mol"^(-1) and "325 kJ mol"^(-1) respectively)

    Calculate the wavelength of the light required to break the bond between two chlorine atoms in a chlorine molecule. The Cl - Cl bond energy is 243 kJ mol^(-1) (h = 6.6 xx 10^(-34) Js, c = 3 xx 10^(8) ms^(-1) , Avogadro's number = 6.02 xx 10^(23) mol^(-1) )

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