How many chlorine atoms will be ionised `Cl to Cl^(-) + e^(-)` by the energy released from the process `Cl + e^(-) to Cl^(-)` for `6.02 xx 10^(23)` atoms (I.P for Cl = 1250 kJ `mol^(-1)` and E.A. = `350 kJ "mole"^(-1)`)

Explanation

To solve the question of how many chlorine atoms will be ionized by the energy released from the process of gaining an electron, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Processes Involved**:
- The ionization process of chlorine can be represented as:
\[
\text{Cl} \rightarrow \text{Cl}^+ + e^-
...