ABC is a triangle . Locate a point in the interior of triangleABC which is equidistant from all the vertices of triangleABC .
In a triangle, locate a point in its interior of which is equidistant from all the sides of triangle.
The base AB of an equilateral Delta ABC of side 2p lies along the X-axis such that the midpoint of AB is at the origin and vertex C is above x-axis. Find coordinates of the vertices of Delta ABC.
If a sin a=b sin B then prove that Delta ABC is isosceles.
If a sin a=b sin B then prove that Delta ABC is isosceles.
ABC is a triangle with vertices A(-8, 3), B(4, 5), C(-6,1). Find the vertices of a parallelogram in this Delta ABC sharing vertex B and having half the area of Delta ABC. Find the area ot the paralelogram so formed.
Prove that the median of Delta ABC divides it into two triangles of equal area. .
If D - ((1)/(5) , (5)/(2) ) , E ( 7, 3) and F ((7)/(2), (7)/(2)) are the mid-point of the sides of Delta ABC , find the coordinates of Delta ABC.
The vertices of a Delta ABC are A (-5,-1), B (3,-5) , C (5,2). Show that the area of the Delta ABC is four times the area of the triangle formed by joining the mid-points of the sides of the triangle ABC.
