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Given P(A) = (3)/(5) and P(B) = (1)/(5)...

Given P(A) ` = (3)/(5) and P(B) = (1)/(5)` . Find P(A or B), if A & B are mutually exclusive events.

Text Solution

Verified by Experts

The correct Answer is:
`P(A cup B)=(4/5)`
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Given P(A) = 3/5 and P(B) = 1/5 . Find P(A or B) , if A and B are mutually excluive events.

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Knowledge Check

  • If A and B are two mutually exclusive events , then :

    A
    `P(A) lt P(bar(B))`
    B
    `P(A) gt P(bar(B))`
    C
    `P(A) lt P(B)`
    D
    None of these

  • If S is a sample space, P(A) = 1/3 P(B) and S = A cup B where A and B are two mutually exclusive events, then P(A) =

    A
    1/4
    B
    1/2
    C
    3/4
    D
    3/8

  • The probability of happening of an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then the probability of neither A nor B is

    A
    0.4
    B
    0.5
    C
    0.2
    D
    0.9

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