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Given that C denotes capacitance of a ca...

Given that `C` denotes capacitance of a capacitor and `V` is the potential difference across its plates. Then the dimensions of `CV^(2)` are same as that of

A

momentum

B

power

C

forces

D

torque

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The correct Answer is:
To find the dimensions of \( CV^2 \), where \( C \) is the capacitance and \( V \) is the potential difference, we can follow these steps: ### Step-by-Step Solution 1. **Identify the dimensions of capacitance \( C \)**: The capacitance \( C \) is defined as the charge \( Q \) per unit potential difference \( V \). The formula is: \[ C = \frac{Q}{V} \] The dimension of charge \( Q \) is \( [I][T] \) (where \( I \) is current and \( T \) is time). The dimension of potential difference \( V \) is \( [M][L^2][T^{-3}][I^{-1}] \) (derived from the formula \( V = W/Q \), where \( W \) is work done, and its dimension is \( [M][L^2][T^{-2}] \)). Therefore, the dimension of capacitance \( C \) can be expressed as: \[ [C] = \frac{[Q]}{[V]} = \frac{[I][T]}{[M][L^2][T^{-3}][I^{-1}]} = [M^{-1}][L^{-2}][T^4][I^2] \] 2. **Identify the dimensions of potential difference \( V \)**: As mentioned earlier, the dimension of potential difference \( V \) is: \[ [V] = [M][L^2][T^{-3}][I^{-1}] \] 3. **Calculate the dimensions of \( V^2 \)**: To find \( V^2 \), we square the dimensions of \( V \): \[ [V^2] = ([M][L^2][T^{-3}][I^{-1}])^2 = [M^2][L^4][T^{-6}][I^{-2}] \] 4. **Combine the dimensions of \( C \) and \( V^2 \)**: Now we can find the dimensions of \( CV^2 \): \[ [CV^2] = [C] \cdot [V^2] = [M^{-1}][L^{-2}][T^4][I^2] \cdot [M^2][L^4][T^{-6}][I^{-2}] \] 5. **Multiply the dimensions**: When we multiply the dimensions, we combine the powers of each base unit: \[ [CV^2] = [M^{-1} \cdot M^2][L^{-2} \cdot L^4][T^4 \cdot T^{-6}][I^2 \cdot I^{-2}] \] This simplifies to: \[ [CV^2] = [M^{1}][L^{2}][T^{-2}][I^{0}] = [M][L^{2}][T^{-2}] \] 6. **Conclusion**: The dimensions of \( CV^2 \) are the same as that of energy, which is given by: \[ [E] = [M][L^2][T^{-2}] \] ### Final Answer: The dimensions of \( CV^2 \) are the same as that of energy.
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Knowledge Check

  • The displacement current flows in the dielectric of a capacitor when the potential difference across its plates-

    A
    becomes zero
    B
    has assumed a constant value
    C
    is increasing with time
    D
    decreasing with time
  • If V denotes te potential difference across the plate of a capacitor of capacitance C , the dimensions of CV^(2) are

    A
    Not expressible in `MLT`
    B
    `MLT^(-2)`
    C
    `M^(2)LT^(-1)`
    D
    `ML^(2)T^(-2)`
  • If L, R , C , and V , respectively , represent inductance , resistance , capacitance and potential difference , then the dimensions of L //RCV are the same as those of

    A
    Charge
    B
    `1//"Charge"`
    C
    Current
    D
    `1//"Current"`
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