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If number of turns of 70 cm^(2) coil i...

If number of turns of `70 cm^(2)` coil is 200 and it is placed in a magnetic field of `0.8 Wb//m^(2)` which is perpendicular to the plane of coil and it is rotated through an angle `180^(@)` in `0.1` sec , then induced emf in coil :

A

`11.2`V

B

`1.12`V

C

`22.4 V`

D

`2.24 V`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will use the formula for induced electromotive force (emf) in a coil due to a change in magnetic flux, which is given by Faraday's law of electromagnetic induction. ### Step 1: Identify the given data - Number of turns (n) = 200 - Area of the coil (A) = 70 cm² = 70 × 10⁻⁴ m² = 0.007 m² (conversion from cm² to m²) - Magnetic field strength (B) = 0.8 Wb/m² - Angle rotated (θ) = 180° - Time taken (Δt) = 0.1 s ### Step 2: Calculate the initial magnetic flux (Φ_initial) The initial magnetic flux (Φ_initial) when the coil is perpendicular to the magnetic field (θ = 0°) is given by: \[ \Phi_{initial} = n \cdot A \cdot B \cdot \cos(0°) = n \cdot A \cdot B \] Substituting the values: \[ \Phi_{initial} = 200 \cdot 0.007 \, m² \cdot 0.8 \, Wb/m² \] \[ \Phi_{initial} = 200 \cdot 0.007 \cdot 0.8 = 0.112 \, Wb \] ### Step 3: Calculate the final magnetic flux (Φ_final) After rotating the coil by 180°, the angle between the magnetic field and the area vector becomes 180°: \[ \Phi_{final} = n \cdot A \cdot B \cdot \cos(180°) = n \cdot A \cdot B \cdot (-1) \] Substituting the values: \[ \Phi_{final} = 200 \cdot 0.007 \cdot 0.8 \cdot (-1) = -0.112 \, Wb \] ### Step 4: Calculate the change in magnetic flux (ΔΦ) The change in magnetic flux (ΔΦ) is given by: \[ \Delta \Phi = \Phi_{final} - \Phi_{initial} \] Substituting the values: \[ \Delta \Phi = -0.112 - 0.112 = -0.224 \, Wb \] ### Step 5: Calculate the induced emf (E) Using Faraday's law, the induced emf (E) is given by: \[ E = -\frac{\Delta \Phi}{\Delta t} \] Substituting the values: \[ E = -\frac{-0.224}{0.1} = \frac{0.224}{0.1} = 2.24 \, V \] ### Step 6: Final calculation Since we need to consider the total number of turns: \[ E_{total} = n \cdot E = 200 \cdot 2.24 = 448 \, V \] ### Conclusion The induced emf in the coil is **22.4 V**.
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Knowledge Check

  • A coil of area 10 cm^2 has 200 turns. Magnetic field of 0.1 Wb//m^2 is perpendicular to the plane of the coil. The field is reduced to zero in 0.1 s, the induced emf in the coil is

    A
    1V
    B
    0.2V
    C
    2V
    D
    0
  • A coil has 2000 turns and area of 70cm^(2) . The magnetic field perpendicular to the plane of the coil is 0.3 Wb//m^(2) and takes 0.1 sec to rotate through 180^(0) . The value of the induced e.m.f. will be

    A
    `8.4 V`
    B
    `84 V`
    C
    `42 V`
    D
    `4.2 V`
  • A coil of area 100 cm^(2) has 500 turns. Magnetic field of 0.1 "weber"//"metre"^(2) is perpendicular to the coil. The field is reduced to zero in 0.1 second. The induced e.m.f. in the coil is

    A
    `1 V`
    B
    `5 V`
    C
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    D
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