Find the equation of the plane that contains the point `(1, 1, 2)`and is perpendicular to each of the planes `2x + 3y - 2z = 5`and `x + 2y - 3z = 8`.

Explanation

To find the equation of the plane that contains the point \( (1, 1, 2) \) and is perpendicular to the planes \( 2x + 3y - 2z = 5 \) and \( x + 2y - 3z = 8 \), we can follow these steps:

### Step 1: Identify the Normal Vectors of the Given Planes
The normal vector of a plane given by the equation \( Ax + By + Cz = D \) is \( \langle A, B, C \rangle \).

1. For the plane \( 2x + 3y - 2z = 5 \):
- Normal vector \( \mathbf{n_1} = \langle 2, 3, -2 \rangle \)

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