The vapour pressure of water at 80^(@)C ...

The vapour pressure of water at `80^(@)C` is 355 mm of Hg. 1 L vessel contains `O_(2)` at `80^(@)C`, which is saturated with water and the total pressure being 760 mm of Hg. The contents of the vessel were pumped into 0.3 L vessel at the same temperature. What is the partial presure of `O_(2)`?

1350 Hg

2178.3 Hg

121.5 Hg

355 Hg

Text Solution

Verified by Experts

The correct Answer is:

(a) Volume of `O_(2)`=1 L
and `P_(O_(2))`=760-355=405 mm Hg
Since, the temperature is constant, using Boyle's law we get
`1 Lxx405 mm=0.3 LxxP'o_(2)
`:.` `P'o_(2) =1350 mmHg`

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The vapour pressure of water at 80^(@) C is 355.5 mm of Hg. A 100 mL vessel contains water saturated with O_2 at 80^(@)C , the total pressure being 760 mm of Hg. The contents of the vessel were pumped into a 50 mL vessel at the same temperature. What is the partial pressure of O_2 ?

1115 mm

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405 mm

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540torr

900torr

1080torr

450torr