In two vessels of 1 litre each at athe same temperature 1g of `H_(2)` and 1g of `CH_(4)` are taken. For these gases:
A
`V_("rms")` values will be same
B
Kinetic energy per mol will be same
C
Total kinetic energy will same
D
Pressure will be same
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we need to analyze the given information about the two gases, hydrogen (H₂) and methane (CH₄), in terms of their properties at the same temperature and in equal volumes.
### Step-by-Step Solution:
1. **Identify the Molar Masses**:
- The molar mass of H₂ (hydrogen) is approximately 2 g/mol.
- The molar mass of CH₄ (methane) is approximately 16 g/mol.
2. **Calculate the Number of Moles**:
- For H₂:
\[
\text{Number of moles of H₂} = \frac{\text{mass}}{\text{molar mass}} = \frac{1 \text{ g}}{2 \text{ g/mol}} = 0.5 \text{ moles}
\]
- For CH₄:
\[
\text{Number of moles of CH₄} = \frac{1 \text{ g}}{16 \text{ g/mol}} = 0.0625 \text{ moles}
\]
3. **Calculate the Root Mean Square (RMS) Velocity**:
- The formula for RMS velocity is:
\[
v_{rms} = \sqrt{\frac{3RT}{M}}
\]
- For H₂:
\[
v_{rms(H₂)} = \sqrt{\frac{3RT}{2}}
\]
- For CH₄:
\[
v_{rms(CH₄)} = \sqrt{\frac{3RT}{16}}
\]
- Since the molar masses are different, the RMS velocities will also differ.
4. **Calculate the Kinetic Energy per Mole**:
- The kinetic energy per mole is given by:
\[
KE = \frac{3}{2}RT
\]
- This value is the same for both gases since it depends only on temperature (T) and the gas constant (R), not on the type of gas.
5. **Total Kinetic Energy**:
- The total kinetic energy for each gas can be calculated as:
\[
\text{Total KE} = \text{Number of moles} \times \text{KE per mole}
\]
- For H₂:
\[
\text{Total KE(H₂)} = 0.5 \text{ moles} \times \frac{3}{2}RT
\]
- For CH₄:
\[
\text{Total KE(CH₄)} = 0.0625 \text{ moles} \times \frac{3}{2}RT
\]
- Since the number of moles is different, the total kinetic energies will also be different.
6. **Pressure Comparison**:
- Using the ideal gas law \( PV = nRT \):
- Since both gases are in 1 liter vessels at the same temperature, the pressure will depend on the number of moles.
- Therefore, the pressure will be different for H₂ and CH₄ because the number of moles is different.
### Conclusion:
- The correct statements are:
- The kinetic energy per mole is the same for both gases.
- The total kinetic energy is different due to the difference in moles.
- The pressures in the vessels will also be different.
To solve the problem, we need to analyze the given information about the two gases, hydrogen (H₂) and methane (CH₄), in terms of their properties at the same temperature and in equal volumes.
### Step-by-Step Solution:
1. **Identify the Molar Masses**:
- The molar mass of H₂ (hydrogen) is approximately 2 g/mol.
- The molar mass of CH₄ (methane) is approximately 16 g/mol.
...
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