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In two vessels of 1 litre each at athe s...

In two vessels of 1 litre each at athe same temperature 1g of `H_(2)` and 1g of `CH_(4)` are taken. For these gases:

A

`V_("rms")` values will be same

B

Kinetic energy per mol will be same

C

Total kinetic energy will same

D

Pressure will be same

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given information about the two gases, hydrogen (H₂) and methane (CH₄), in terms of their properties at the same temperature and in equal volumes. ### Step-by-Step Solution: 1. **Identify the Molar Masses**: - The molar mass of H₂ (hydrogen) is approximately 2 g/mol. - The molar mass of CH₄ (methane) is approximately 16 g/mol. 2. **Calculate the Number of Moles**: - For H₂: \[ \text{Number of moles of H₂} = \frac{\text{mass}}{\text{molar mass}} = \frac{1 \text{ g}}{2 \text{ g/mol}} = 0.5 \text{ moles} \] - For CH₄: \[ \text{Number of moles of CH₄} = \frac{1 \text{ g}}{16 \text{ g/mol}} = 0.0625 \text{ moles} \] 3. **Calculate the Root Mean Square (RMS) Velocity**: - The formula for RMS velocity is: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] - For H₂: \[ v_{rms(H₂)} = \sqrt{\frac{3RT}{2}} \] - For CH₄: \[ v_{rms(CH₄)} = \sqrt{\frac{3RT}{16}} \] - Since the molar masses are different, the RMS velocities will also differ. 4. **Calculate the Kinetic Energy per Mole**: - The kinetic energy per mole is given by: \[ KE = \frac{3}{2}RT \] - This value is the same for both gases since it depends only on temperature (T) and the gas constant (R), not on the type of gas. 5. **Total Kinetic Energy**: - The total kinetic energy for each gas can be calculated as: \[ \text{Total KE} = \text{Number of moles} \times \text{KE per mole} \] - For H₂: \[ \text{Total KE(H₂)} = 0.5 \text{ moles} \times \frac{3}{2}RT \] - For CH₄: \[ \text{Total KE(CH₄)} = 0.0625 \text{ moles} \times \frac{3}{2}RT \] - Since the number of moles is different, the total kinetic energies will also be different. 6. **Pressure Comparison**: - Using the ideal gas law \( PV = nRT \): - Since both gases are in 1 liter vessels at the same temperature, the pressure will depend on the number of moles. - Therefore, the pressure will be different for H₂ and CH₄ because the number of moles is different. ### Conclusion: - The correct statements are: - The kinetic energy per mole is the same for both gases. - The total kinetic energy is different due to the difference in moles. - The pressures in the vessels will also be different.

To solve the problem, we need to analyze the given information about the two gases, hydrogen (H₂) and methane (CH₄), in terms of their properties at the same temperature and in equal volumes. ### Step-by-Step Solution: 1. **Identify the Molar Masses**: - The molar mass of H₂ (hydrogen) is approximately 2 g/mol. - The molar mass of CH₄ (methane) is approximately 16 g/mol. ...
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Knowledge Check

  • A reaction system in equilibrium according to reaction 2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g) in one litre vessel at a given temperature was found to be 0.12 mole each of SO_(2) and SO_(3) and 5 mole of O_(2) In another vessell of one litre contains 32 g of SO_(2) at the same temperature. What mass of O_(2) must be added to this vessel in order that at equilibrium 20% of SO_(2) is oxidized to SO_(3) ?

    A
    `0.4125`
    B
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    C
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    D
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    A
    `1:1`
    B
    `1:2`
    C
    `2:1`
    D
    `3:2`
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    A
    Pressure in I is the maximum.
    B
    Number of molecules
    C
    Average molecular velocity
    D
    Average molecular kinetic energy
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