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Of BF(3) " and " NF(3), dipolemoment is ...

Of `BF_(3) " and " NF_(3)`, dipolemoment is observed for `NF_(3)` and not for `BF_(3)`. Why?

Text Solution

Verified by Experts

In polyatomic molecules the dipolemoment of the molecule is the resultant of vector sum of the dipolemoment of various bonds.
`BF_(3)` molecule has symmetric planar triangular structure. The threee equal bond dipoles point to the corners of a triangle at an angle of `120^(@)1` and cancel the effect on each other.

The three bond moments give a net sum of zero as the resultant of any two is equal and opposite to the third.

In `NF_(3)` the three N - F bonds have dipolemoments. Also the lone pair present on nitrogen atom show dipolemoment in the opposite direction to the resultant N - F bond dipolemoments.
Though the orbital dipolemoment due to lone pair and the resultant dipole moment of three N - F bonds are in opposite direction there remains some resultant dipolemoment since they do not cancel completely.
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Knowledge Check

  • The dipole moment of BF_(3) is zero because

    A
    The electronegativity difference between boron and fluorine molecule
    B
    It is a covalent molecule
    C
    It is a tetra atomic molecule
    D
    It is having trigonal planar geometry.
  • B - F bond order of BF_(3) is

    A
    1
    B
    2
    C
    3
    D
    `4//3`
  • Identify the correct statements from the following. (1) The dipole moment of CO_(2) and BF_(3) is zero (2) The dipole moment of NF_(3) is higher than the diople moment of NH_(3) (3) The dipole moment of HI is lower than the dipole moment of HCl

    A
    1, 3
    B
    1, 2
    C
    2, 3
    D
    1, 2,3
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