Home
Class 12
CHEMISTRY
Calculate the mass of sodium acetate (CH...

Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make 500 ml. of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245g `mol^(-1)`.

Text Solution

Verified by Experts

Molar mass of `CH_(3)COONa=82.0245g mol^(-1)`
1 mol = 82.02459
0.375 mol = ?
`0.375xx82.0245` gm
1000 ml. contain `" "0.375xx82.0245g`
500 ml. contain `" "?`
= `500/1000xx0.375xx82.0245`
= 15.375 gm.
`therefore` The mass of `CH_(3)COONa` present in 500 ml = 15.375 gm.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STOICHIOMETRY

    VGS PUBLICATION-BRILLIANT|Exercise LONG ANSWER QUESTION|13 Videos

  • STOICHIOMETRY

    VGS PUBLICATION-BRILLIANT|Exercise ADDITIONAL QUESTIONS & ANSWERS|10 Videos

  • STOICHIOMETRY

    VGS PUBLICATION-BRILLIANT|Exercise ADDITIONAL QUESTIONS & ANSWERS|10 Videos

  • STATES OF MATTER : GASES AND LIQUIDS

    VGS PUBLICATION-BRILLIANT|Exercise ADDITIONAL QUESTION & ANSWERS|10 Videos

  • THE P-BLOCK ELEMENTS - GROUP 13

    VGS PUBLICATION-BRILLIANT|Exercise LONG ANSWER QUESTIONS|3 Videos

Similar Questions

Explore conceptually related problems

Calculate the mass of sodium acetate (CH_(3)COONa) required to make 500 ml of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g "mol"^(-1)

Calculate the mass of Na_(2)CO_(3) required to prepare 250 ml of 0.5 N solution.

Knowledge Check

  • Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]

    A
    1M
    B
    1.02 M
    C
    1.2 M
    D
    0.98 M

    • Similar Questions

    Explore conceptually related problems

    Calculate the mass of urea ("NH"_(2)"CONH"_(2)) required in making 2.5 kg of 0.25 molar aqueous solution. We know that molarity (m) =("Moles of solute")/("Mass of solvent in kg") and moles of soute =("Mass of solute")/("Molar mass of solute") So, find the molar mass of solute by adding atomic masses of different element present in it and mass by using the formula, Molality =("Mass of solute/molar mass of solute")/("Mass of solvent in kg")

    Calculate the molarity of a solution contaịning 10g of NaOH in 500 ml of solution.

    Calculate the molarity of a solution containing 5g of NaOH in 500 mL solution.

    Calculate the weight of sodium chloride present in 250mL of 0.1N solution.

    Jagadeesh: How can we predict the nature of a salt, sodium acetate (CH_3COONa) ? Leela: Explained the doubt of Jagadeesh by asking some questions. Here their conversation is given in incomplete sentence. Frame the questions and fill in it. Leela : ...................................................................? Jagadesh : CH_3COONa (Sodium acetate) is basic in nature.

    0.63 grams of a dioic acid required 50mL of 0.2M NaOH for neutralisation. Calculate the molar mass of acid .

    Jagadeesh: How can we predict the nature of a salt, sodium acetate (CH_3COONa) ? Leela: Explained the doubt of Jagadeesh by asking some questions. Here their conversation is given in incomplete sentence. Frame the questions and fill in it. 3) Leela : .................................................................? Jagadeesh : CH_3COOH+NaOH to CH_3COONa+H_2O

    Home
    Profile