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If the ionization energy of He^(+) is 5...

If the ionization energy of `He^(+)` is 54.4 eV then

A

I.E of H is 13.6 eV and that of `Li^(+2) 122.4eV`

B

I.E of H is 13.6 eV and that of `Li^(+2)` cannot be determined

C

I.E of H is 13.6 eV and that of `Li^(+2)` is 27.2 eV

D

All of the above are wrong

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • 1 mol of He^(+) ion is excited. Spectral analysis showed existence of 50% ions in 3rd level, 25% in 2nd level and remaining 25% in ground state. Ionization energy of He^(+) is 54.4 eV , calculate total energy evolved when all the ions retirn ground state.

    A
    `331.13xx10^(4) J`
    B
    `400.14 xx10^(4) J`
    C
    `10^(4) J`
    D
    `6.66xx10^(4) J`

  • If first orbit energy of He^(+) is -54.4 eV, then the second orbit energy will be

    A
    `-54.4 eV`
    B
    `-13.6 eV`
    C
    `-27.2 eV`
    D
    `+27.2 eV`

  • The work function of the metal A is equal to the ionization energy of the hydrogen atom in the first excited state. The work function of the metal B is equal to the ionization energy of the hydrogen atom in the first excited state. The work function of the metal B is equal to the ionization energy of He^+ ion in the second orbit. Photons of the same energy E are incident on both A and B. The maximum kinetic energy of photoelectrons emitted from A is twice that of photoelectrons emitted from B . Value of E (in eV) is

    A
    23.8 eV
    B
    20.8 eV
    C
    32.2 eV
    D
    24.6 eV

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    If the first ionisation energy of H-atom is 13.6 eV, then the second ionisation energy of He-atom is :

    If the first ionisation energy of H-atom is 13.6 eV, then the second ionisation energy of He-atom is :

    If the first ionization enthalpy of Li is 5.4 eV and the elec- tron gain enthalpy of chlorine is 3.6 eV then the Delta H in kcal/mole for the reaction will be Li(g)+Cl(g) to Li^(+) (g) Cl^(-) (g) (Presume that the pressure is so low that the ions do not combine with each other)

    The ionization energy of H-atom is 13.6 eV. The ionization energy of Li^(2+) ion will be:

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