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If the wavelength of light emitted by a...

If the wavelength of light emitted by a sodium vapour lamp is 5893 A then the numebr of photons emitted in 5 hour by a 50 W lamp will be

A

`7.4 xx10^(20)` photons

B

`4.46 xx10^(22)` photons

C

`2.7 xx10^(24)` photons

D

`5.4 xx10^(23)` photons

Text Solution

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The correct Answer is:
To solve the problem of finding the number of photons emitted by a sodium vapor lamp with a wavelength of 5893 Å in 5 hours by a 50 W lamp, we will follow these steps: ### Step 1: Convert Time to Seconds First, we need to convert the time from hours to seconds. \[ \text{Time in seconds} = 5 \text{ hours} \times 60 \text{ minutes/hour} \times 60 \text{ seconds/minute} = 18000 \text{ seconds} \] ### Step 2: Calculate Total Energy Next, we calculate the total energy emitted by the lamp using the formula: \[ \text{Energy} = \text{Power} \times \text{Time} \] Given that the power of the lamp is 50 W: \[ \text{Energy} = 50 \text{ W} \times 18000 \text{ s} = 900000 \text{ J} = 9 \times 10^5 \text{ J} \] ### Step 3: Calculate Energy of One Photon Now, we need to calculate the energy of one photon emitted by the lamp. The energy of a photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] Where: - \( h \) (Planck's constant) = \( 6.626 \times 10^{-34} \text{ J s} \) - \( c \) (speed of light) = \( 3 \times 10^8 \text{ m/s} \) - \( \lambda \) (wavelength) = \( 5893 \text{ Å} = 5893 \times 10^{-10} \text{ m} \) Substituting the values: \[ E = \frac{(6.626 \times 10^{-34} \text{ J s}) \times (3 \times 10^8 \text{ m/s})}{5893 \times 10^{-10} \text{ m}} \] Calculating the energy: \[ E \approx \frac{1.9878 \times 10^{-25}}{5893 \times 10^{-10}} \approx 3.37 \times 10^{-19} \text{ J} \] ### Step 4: Calculate the Number of Photons Finally, we can find the number of photons emitted by dividing the total energy by the energy of one photon: \[ \text{Number of photons} = \frac{\text{Total Energy}}{\text{Energy of one photon}} = \frac{9 \times 10^5 \text{ J}}{3.37 \times 10^{-19} \text{ J}} \] Calculating this gives: \[ \text{Number of photons} \approx 2.67 \times 10^{24} \] ### Final Answer Thus, the number of photons emitted in 5 hours by a 50 W sodium vapor lamp is approximately: \[ \text{Number of photons} \approx 2.7 \times 10^{24} \]
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Knowledge Check

  • If mean wavelength of light radiated by 100 W lamp is 5000 Å , then number of photons radiated per second are

    A
    `3 xx 10^(23)`
    B
    `2.5 xx 10^(22)`
    C
    `2.5 xx 10^(20)`
    D
    `5 xx 10^(17)`
  • Calculate the number of photons emitted in 10 hour by 60 W sodium lamp (lamda_(photon)=5893Å)

    A
    `6.40xx10^(24)`
    B
    `12.80xx10^(24)`
    C
    `19.20xx10^(24)`
    D
    `25.60xx10^(24)`
  • The number of photons emitted in 10 hours by a 60 W sodiu lamp ( lambda = 5893 Å) will be :-

    A
    `1.6 xx 10^(24)`
    B
    `3.2 xx 10^(24)`
    C
    `6.4 xx 10^(24)`
    D
    `8 xx 10^(24)`
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