Home
Class 12
CHEMISTRY
Calculate relative lowering of vapour pr...

Calculate relative lowering of vapour pressure of 0.161 molal aqueous solution

Text Solution

AI Generated Solution

To calculate the relative lowering of vapor pressure of a 0.161 molal aqueous solution, we will follow these steps: ### Step 1: Understand the formula for relative lowering of vapor pressure The relative lowering of vapor pressure can be expressed as: \[ \frac{P_0 - P}{P_0} = \frac{n_{solute}}{n_{solvent}} \] where \(P_0\) is the vapor pressure of the pure solvent, \(P\) is the vapor pressure of the solution, \(n_{solute}\) is the number of moles of solute, and \(n_{solvent}\) is the number of moles of solvent. ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate relative lowering of vapour pressure in an aqueous solution of CaCI_(2) haing 1 mole of CaCI_(2) dissolve3d in 324 g of water if degree of dissociain is 60%

The relative lowering in vapour pressure is:

The relative lowering of vapour pressure of an aqueous solution containing a non-volatile solute, is 0.0125. The molality of the solution is

The vapour pressure of a pure liquid at 25^(@)C is 100 mm Hg. Calculate the relative lowering of vapour pressure if the mole fraction of solvent in solution is 0.8.