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Calculate relative lowering of vapour pr...

Calculate relative lowering of vapour pressure of 0.161 molal aqueous solution

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To calculate the relative lowering of vapor pressure of a 0.161 molal aqueous solution, we will follow these steps: ### Step 1: Understand the formula for relative lowering of vapor pressure The relative lowering of vapor pressure can be expressed as: \[ \frac{P_0 - P}{P_0} = \frac{n_{solute}}{n_{solvent}} \] where \(P_0\) is the vapor pressure of the pure solvent, \(P\) is the vapor pressure of the solution, \(n_{solute}\) is the number of moles of solute, and \(n_{solvent}\) is the number of moles of solvent. ...
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Knowledge Check

  • Calculate relative lowering of vapour pressure in an aqueous solution of CaCI_(2) haing 1 mole of CaCI_(2) dissolve3d in 324 g of water if degree of dissociain is 60%

    A
    `(1)/(19)`
    B
    `(3)/(19)`
    C
    `(11)/(101)`
    D
    `(2.2)/(19)`
  • The relative lowering in vapour pressure is:

    A
    `prop X_("solute")`
    B
    `prop (1)/(X_("solute"))`
    C
    `=X_("solute")`
    D
    `prop m`
  • Lowering of vapour pressure in 1 motal aqueous solution at 100^@C is

    A
    13.44 mm Hg
    B
    14.12 mm Hg
    C
    31.2 mm Hg
    D
    35.2 mm Hg
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