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The displacement of a particle moving in...

The displacement of a particle moving in a straight line is given by `x=2t^2+t+5` where x is expressed in metre and t in second. The acceleration at t = 2 s is

A

`4 ms^(-2)`

B

`8 ms^(-2)`

C

`10 ms^(-2)`

D

`15 ms^(-2)`

Text Solution

Verified by Experts

Distance covered in 2 s is,
`s=ut+1/2g t^2=u(2)+1/2xx10xx2^2=2u+20`
Distance covered in next is,
`"S"^2=[u(3)+1/2xx10(3)^2]-(2u+20)`
`3u+45-2u-20`
`"S"^1=u+25`
Since,`s=s^1`
`2u+20=u+25`
`u=5`
`s=2xx5+20=30m`
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Knowledge Check

  • The motion of a particle along a straight line is described by the function x = (2t-3)^(2) where x is in metres and t is in seconds . The acceleration of the particle at =2s is

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