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Assertion (A) Cu^(2+) iodine is not know...

Assertion (A) `Cu^(2+)` iodine is not known.
Reason (R ) `Cu^(2+)` oxidises `I^(-)` to iodine.

A

Both assertion and reason are true, and reason is the correct explanation of the assertion.

B

Both assertion and reason are true but reason is not the correct explanation of assertion.

C

Assertion is not true but reason is true.

D

Both assertion and reason are false.

Text Solution

Verified by Experts

The correct Answer is:
A
Assertion and reason both are correct and reason is the correct explanation of assertion.
Copper (II) iodide `(CuI_(2))` is not known because `Cu^(2+)` oxidises `I^(-)` to Iodine.
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Assertion.Copper (II) iodide is not known. Reason. Cu^(2+) oxidizes I^(-) to iodine.

Assertion(A) Cu is less reactive than hydrogen. Reason(R) E_(Cu^(2+)//Cu)^(o+) is negative.

Knowledge Check

  • Assertion : Cu^(2+) iodide is not known Reason : Cu^(2+) oxidises I^(-) to iodine.

    A
    Both assertion and reason are true and reason is the correct explanation of the assertion .
    B
    Both assertion and reason are true but reason is not the correc explanation of assertion.
    C
    Assertion is not true for reason is true
    D
    Both assertion and reason are false.

  • Assertion: Cu^(2+) iodide is not known. Reason: Cu^(2+) oxidises I– to iodine.

    A
    Both assertion and reason are True, and reason is the correct explanation of the assertion.
    B
    Both assertion and reason are True, but reason is not the correct explanation of the assertion.
    C
    Assertion is not True, but reason is True.
    D
    Both assertion and reason are False.

  • The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Select the correct chemical change:

    A
    `Cu+Dil.H_(2)SO_(4) to CuSO_(4)+H_(2)(g)`
    B
    `Cu+dil.HNO_(3) to Cu(NO_(3))_(2)+N_(2)O(g)`
    C
    `CuSO_(4)(aq.)+KCN(excess)toK_(2)[Cu(CN)_(4)]`
    D
    `CuSO_(4)(aq.)+NH_(4)OH to Cu(OH)_(2)darr`

    • Similar Questions

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    Assertion: Cu is stronger reducing agent than H^(+) . Reason: E^(0) of Cu^(2+)//Cu is negative.

    Assertion (A): Iodine forms IF_(7) . Reason (R ): In iodine 5d-subshell is available in the valence shell to expand its octet.

    The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Select the correct chemical change:

    The unique behaviour of CU, having a positive E^(@) (reduction potential) accounts for its inability to liberate H_(2) from acids,. Only oxidising acids (nitric acid and hot concentrated sulphuric acid) react with Cu. The high energy of transform Cu(s) to Cu^(2+)(aq.) is not balanced by its hydration enthalpy. On the other hand, All Cu(II) halides are known except iodide. in this case, Cu^(2+) oxidises I^(-) to I_(2) : 2Cu^(2+)+4I^(-) to 2CuI(s)+I_(2) However, copper (I) compounds are unstable in aqueous solution annd undergo disproportionation. 2Cu^(+)(aq.)toCu^(2+)(aq.)+Cu The stability of Cu^(2+)(aq.) rather than Cu^(+)(aq) is due to the much more negative Delta_(Hyd) of Cu^(2+)(aq.) than Cu^(+)(aq.) Q. Consider the following transformation: CuSO_(4)(aq.)+KI(excess)to product Select the correct statement:

    Assertion (A): ICl on hydrolysis gives HI and HOCl. Reason (R ): Water can attack iodine more readily.

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