Find the distance of the plane `2x 3y + 4z 6 = 0`from the origin.

Explanation

To find the distance of the plane given by the equation \(2x - 3y + 4z + 6 = 0\) from the origin, we can use the formula for the distance \(D\) from a point to a plane. The formula is:

\[ D = \frac{|Ax_0 + By_0 + Cz_0 + D|}{\sqrt{A^2 + B^2 + C^2}} \]

Where:
- \(A\), \(B\), and \(C\) are the coefficients of \(x\), \(y\), and \(z\) in the plane equation \(Ax + By + Cz + D = 0\).
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