Let there be a uniform electric field "E" existing along the positive X-direction.Assume electric potential to be zero at the origin.Potential at the point `x=x_(0)` is

A uniform electric field E_0 is directed along positive y-driection. Find the change in electric potential energy of a positive test charge q_0 when it is displaced in this field from y_i=a to y_f=2a along the y-axis.

Electric intensity is directed along the direction at which electric potential

A uniform electric field of magnitude 250 V// m is directed in the positive x-direction. A+12muC charge moves from the origin to the point (x, y) = (20.0 cm, 5.0 cm). (a) What was the change in the potential energy of this charge? (b) Through what potential difference did the charge move?

Consider a uniform electric field in the hat (z) direction. The potential is a constant.

A graph of the x-component of the electric field as a function of x in a region of space is shown in figure. The y- and z-components of the electric field are zero in this region. If the electric potential is 10 V at the origin, then the potential at x = 2.0 m is

A unifrom electric field having a magnitude E_(0) and direction along the positive X-axis exists. If the protential V is zero at x = 0 , then its value at X = +x will be

Assume that an electric field vecE=30x^2hatj exists in space. Then the potential difference V_A-V_O , where V_O is the potential at the origin and V_A the potential at x=2m is: