Calculate the number of molecules of sulphur `(S_(8))` present in 16 g of solid sulphur.

Answer

`3.76 xx 10^(22)` molecules

Explanation

1 mole of solid sulphur (S8) = 8 × 32g = 256g i.e., 256g of solid sulphur contains = 6.022 × 1023 molecules
Then, 16g of solid sulpur contains `=6.022xx10^(23)//256=16` molecules
`= 3.76 × 10^(22)` molecules