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The ratio of powers of a thin convex and...

The ratio of powers of a thin convex and thin concave lens is 3/2 and equivalent focal length of their combination is 30 cm. Then their focal lengths respectively are

A

75, -50

B

75, 50

C

10, -15

D

`-75, 50`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the relationship between power and focal length The power \( P \) of a lens is related to its focal length \( f \) by the formula: \[ P = \frac{1}{f} \] where \( f \) is in meters. For a convex lens, the power is positive, and for a concave lens, the power is negative. ### Step 2: Set up the ratio of powers Given that the ratio of the powers of the thin convex lens \( P_c \) to the thin concave lens \( P_n \) is: \[ \frac{P_c}{P_n} = \frac{3}{2} \] Let’s denote the power of the concave lens as \( P_n = -2p \) (negative because it is concave) and the power of the convex lens as \( P_c = 3p \) (positive). ### Step 3: Write the equation for equivalent focal length The equivalent power \( P \) of the combination of the two lenses is given by: \[ P = P_c + P_n = 3p - 2p = p \] We also know that the equivalent focal length \( f \) of the combination is 30 cm, which can be converted to meters as \( 0.3 \) m. Thus, the power of the combination is: \[ P = \frac{1}{f} = \frac{1}{0.3} = \frac{10}{3} \text{ D} \] ### Step 4: Set up the equation From the previous steps, we have: \[ p = \frac{10}{3} \] ### Step 5: Find the focal lengths Now we can find the individual focal lengths of the lenses. 1. **Focal length of the convex lens \( f_c \)**: \[ f_c = \frac{1}{P_c} = \frac{1}{3p} = \frac{1}{3 \times \frac{10}{3}} = \frac{1}{10} \text{ m} = 10 \text{ cm} \] 2. **Focal length of the concave lens \( f_n \)**: \[ f_n = \frac{1}{P_n} = \frac{1}{-2p} = \frac{1}{-2 \times \frac{10}{3}} = \frac{1}{-\frac{20}{3}} = -\frac{3}{20} \text{ m} = -15 \text{ cm} \] ### Final Result Thus, the focal lengths of the lenses are: - Focal length of the convex lens \( f_c = 10 \text{ cm} \) - Focal length of the concave lens \( f_n = -15 \text{ cm} \) ### Summary The focal lengths of the thin convex and thin concave lenses are \( 10 \text{ cm} \) and \( -15 \text{ cm} \), respectively. ---
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Knowledge Check

  • A comvex lens and a concave lens are placed in contact. The ratio of magnitude of the power of the convex lens to that of the concave lens is 4:3. If the focal length of the convex lens is 12 cm, then the focal length of the combination will be

    A
    16 cm
    B
    24 cm
    C
    32 cm
    D
    48 cm
  • The power of a convex lens of focal length 5 cm is

    A
    `+20 D`
    B
    `+50 D`
    C
    `-20 D`
    D
    `-50 D`
  • When a thin convex lens is put in contact with a thin concave lens of the same focal length (f), then the resultant combination has focal length equal to

    A
    f/2
    B
    2f
    C
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    D
    `oo`
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