Give the order of the following :
Planck's constant (`6.63xx10^(-34)`J-s)

Answer

To find the order of Planck's constant, given as \( 6.63 \times 10^{-34} \) J-s, we will follow these steps:

### Step 1: Identify the components of the number
The number is in the scientific notation form \( a \times 10^b \), where:
- \( a = 6.63 \)
- \( b = -34 \)

### Step 2: Determine the case based on the value of \( a \)
Since \( a = 6.63 \) is greater than 5, we will use Case 2 from the explanation provided.

### Step 3: Calculate the order
According to Case 2:
- If \( a \) is greater than or equal to 5, the order is calculated as:
\[ \text{Order} = b + 1 \]
In our case:
- \( b = -34 \)

So we calculate:
\[ \text{Order} = -34 + 1 = -33 \]

### Conclusion
The order of Planck's constant \( 6.63 \times 10^{-34} \) J-s is \( -33 \).

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