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Explain with examples (i) Atomic number,...

Explain with examples (i) Atomic number, (ii) Mass number, (iii) Isotopes and (iv) Isobars. Give any two uses of isotopes

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(i) Atomic number: The atomic number of an element is the total number of protons present in the atom of that element. For example, nitrogen has 7 protons in its atom. Thus, the atomic number of nitrogen is 7
(ii) Mass number: The mass number of an elements is the sum of the number of protons and neutrons present in the atom of that element. For example, the atom of boron has 5 protons and 6 neutrons So, the mass number of boron is 5 +6 11
(ii) Isotopes. These are atoms of the same element having the same atomic number, but different mass numbers. For example, chlorine has two isotopes with atomic number 17 but mass numbers 35 and 37 represented by `(35)/(17)Cl,(37)/(17)Cl`
(iv) Isobars: These are atoms having the same mass number, but different atomic numbers ie isobars are atoms of different elements having the same mass number. For example, Ne has atomic number 10 and sodium has atomic number 11 but both of them have mass numbers as 22 represented by
`(22)/(10)Ne. (22)/(11)Ne`
Two uses of isotopes:
`to ` One isotopes of uranium is used as a fuel in a nuclear reactors.
`to` One isotopes of cobalt is used in the treatment of cancer.
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Knowledge Check

  • If a radioactive isotope with atomic number A and mass number M emits an alpha- particle, the atomic number and mass number of that new isotope will become

    A
    `A -2, M -4`
    B
    `A -2, M`
    C
    `A, M -2`
    D
    `A -4, M -2`
  • Isotopes are the atoms of same element, they have same atomic number but different mass numbers. Isotopes have different number of neutrons in their nucleus . If an element exists in two isotopes having atomic masses 'a' and 'b' in the ratio m:n, then average atomic mass will be (mxxa+nxxb)/(m+n) Different isotopes of same element have same position in the periodic table. the elemens which have single isotope are called monoisotropic elements. Greater is the percentage composition of an isotope, more will be its abundance in nature. .^(12)C and .^(14)C isotopes are found at 98% and 2% respectively in any sample. then, the number of .^(14)C atoms in 12g of the sample will be:

    A
    1.5 mole atoms
    B
    `1.032xx10^(22)` atoms
    C
    `2.06xx10^(21)` atoms
    D
    2g atoms
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