`{:(" Column X "," Column Y "),("a. 8 g " CH_(4) ," i. 0.1 mol "),("b. 1.7 g NH"_(3) ," ii. 0.5 mol "),("c. HCHO "," iii. 40% carbon "),("d. "C_(6)H_(12)O_(6) ," iv. Vapour density = 15 "):}`

Answer

To solve the problem of matching the compounds in Column X with the corresponding values in Column Y, we will analyze each option step by step.

### Step 1: Analyze Column X - Option A (8 g of CH₄)
1. **Determine the molar mass of CH₄ (methane)**:
- Carbon (C) = 12 g/mol
- Hydrogen (H) = 1 g/mol
- Molar mass of CH₄ = 12 + (4 × 1) = 16 g/mol

2. **Calculate moles from 8 g of CH₄**:
- Moles = mass (g) / molar mass (g/mol)
- Moles of CH₄ = 8 g / 16 g/mol = 0.5 mol

3. **Match with Column Y**:
- From Column Y, the matching option is **ii. 0.5 mol**.

### Step 2: Analyze Column X - Option B (1.7 g of NH₃)
1. **Determine the molar mass of NH₃ (ammonia)**:
- Nitrogen (N) = 14 g/mol
- Hydrogen (H) = 1 g/mol
- Molar mass of NH₃ = 14 + (3 × 1) = 17 g/mol

2. **Calculate moles from 1.7 g of NH₃**:
- Moles of NH₃ = 1.7 g / 17 g/mol = 0.1 mol

3. **Match with Column Y**:
- From Column Y, the matching option is **i. 0.1 mol**.

### Step 3: Analyze Column X - Option C (HCHO)
1. **Determine the molar mass of HCHO (formaldehyde)**:
- Hydrogen (H) = 1 g/mol
- Carbon (C) = 12 g/mol
- Oxygen (O) = 16 g/mol
- Molar mass of HCHO = 1 + 12 + 16 = 30 g/mol

2. **Calculate percentage of carbon**:
- Mass of carbon = 12 g
- Percentage of carbon = (mass of carbon / molar mass) × 100 = (12 g / 30 g) × 100 = 40%

3. **Vapor density calculation**:
- Vapor density (VD) = Molecular weight / 2
- VD = 30 g/mol / 2 = 15

4. **Match with Column Y**:
- From Column Y, the matching options are **iii. 40% carbon** and **iv. Vapor density = 15**.

### Step 4: Analyze Column X - Option D (C₆H₁₂O₆)
1. **Determine the molar mass of C₆H₁₂O₆ (glucose)**:
- Carbon (C) = 12 g/mol
- Hydrogen (H) = 1 g/mol
- Oxygen (O) = 16 g/mol
- Molar mass of C₆H₁₂O₆ = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol

2. **Calculate percentage of carbon**:
- Mass of carbon = 6 × 12 = 72 g
- Percentage of carbon = (72 g / 180 g) × 100 = 40%

3. **Vapor density calculation**:
- VD = 180 g/mol / 2 = 90

4. **Match with Column Y**:
- From Column Y, the matching option is **iii. 40% carbon** (but this is already matched with HCHO), and the vapor density does not match any options.

### Final Matching:
- A - ii. 0.5 mol
- B - i. 0.1 mol
- C - iii. 40% carbon and iv. Vapor density = 15
- D - Not matched as per the given options.