Which has more number of atoms ? 1.0 g Na or 1.0 g Mg

Answer

To determine which has more number of atoms between 1.0 g of sodium (Na) and 1.0 g of magnesium (Mg), we can follow these steps:

### Step 1: Determine the molar mass of sodium and magnesium.
- The atomic mass of sodium (Na) is approximately 23 g/mol.
- The atomic mass of magnesium (Mg) is approximately 24 g/mol.

### Step 2: Calculate the number of moles in 1.0 g of sodium.
Using the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
For sodium:
\[ \text{Number of moles of Na} = \frac{1.0 \, \text{g}}{23 \, \text{g/mol}} \approx 0.0435 \, \text{mol} \]

### Step 3: Calculate the number of atoms in 1.0 g of sodium.
Using Avogadro's number (\(6.022 \times 10^{23}\) atoms/mol):
\[ \text{Number of atoms of Na} = \text{Number of moles} \times \text{Avogadro's number} \]
\[ \text{Number of atoms of Na} = 0.0435 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 2.62 \times 10^{22} \, \text{atoms} \]

### Step 4: Calculate the number of moles in 1.0 g of magnesium.
For magnesium:
\[ \text{Number of moles of Mg} = \frac{1.0 \, \text{g}}{24 \, \text{g/mol}} \approx 0.0417 \, \text{mol} \]

### Step 5: Calculate the number of atoms in 1.0 g of magnesium.
\[ \text{Number of atoms of Mg} = 0.0417 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 2.51 \times 10^{22} \, \text{atoms} \]

### Step 6: Compare the number of atoms in sodium and magnesium.
- Number of atoms in 1.0 g of sodium: \(2.62 \times 10^{22}\) atoms
- Number of atoms in 1.0 g of magnesium: \(2.51 \times 10^{22}\) atoms

### Conclusion:
1.0 g of sodium has more atoms than 1.0 g of magnesium.