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In a compound C(x)H(y)O(z) , the mass % ...

In a compound `C_(x)H_(y)O_(z)` , the mass % of C and H is `6:1` and the amount of oxygen present is equal to the half of the oxygen required to react completely `C_(x)H_(y)`. Find the empirical formula of the compound.

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The correct Answer is:
`C_(2)H_(4)O_(3)`
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