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Write True/False: In Redox reaction fi...

Write True/False:
In Redox reaction first oxidation take place.

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To determine whether the statement "In a redox reaction, first oxidation takes place" is true or false, we need to analyze the nature of redox reactions. ### Step-by-Step Solution: 1. **Understanding Redox Reactions**: - A redox (reduction-oxidation) reaction involves the transfer of electrons between two species. One species undergoes oxidation (loses electrons), while the other undergoes reduction (gains electrons). 2. **Simultaneous Process**: - In a redox reaction, oxidation and reduction occur simultaneously. This means that when one substance is oxidized, another substance is being reduced at the same time. 3. **Analyzing the Statement**: - The statement claims that oxidation occurs first in a redox reaction. However, since oxidation and reduction happen at the same time, it is incorrect to say that one occurs before the other. 4. **Conclusion**: - Therefore, the statement "In a redox reaction, first oxidation takes place" is **False**. ### Final Answer: **False**
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Knowledge Check

  • beta -oxidation takes place in

    A
    Matrix of mitochondria
    B
    Cell cytoplasm
    C
    Inter mitochondrial chamber
    D
    Ribosomes

  • Where does oxidation take place?

    A
    Where there is ready access to the atmosphere and oxygenated waters.
    B
    Where there are plants.
    C
    Where there is moisture in air.
    D
    In mountainous regions.

  • In electrolysis , oxidation takes place at

    A
    anode
    B
    cathode
    C
    both at the anode as well as cathode
    D
    the surface of electrolyte solution

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    Oxidation takes place with -

    Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. Which of the following reactions is/are correctly indicated?

    Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. The reaction Cl_(2)to Cl^(-)+ClO_(3)^(-) is:

    Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. Select the correct statement:

    Oxidation and reduction process involves the transaction of electrons. Loss of electrons is oxidation and the gain of electrons is reduction. It is thus obvious that in a redox reaction, the oxidant is reduced by accepting the electrons and the reductant is oxidised by losing electrons. The reactions in which a species disproportionates into two oxidation states (lower and higher) are called disproportionation reactions. In electrochemical cells, redox reaction is involved, i.e., oxidation takes place at anode and reduction at cathode. Detennine the change in oxidation number of sulphur in H_(2)S and SO_(2) respectively in the following reaction: 2H_(2)S+SO_(2) to 2H_(2)O+3S

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