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6 xx 10^(–3) mole K(2)Cr(2)O(7) reacts c...

`6 xx 10^(–3)` mole `K_(2)Cr_(2)O_(7)` reacts completely with `9 xx 10^(–3)` mole `X^(n+)` to give `XO_(3)^(-)` and `Cr^(3+)`. Find the value of X.

Text Solution

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`K_(2)Cr_(2)O_(7)+X^(n+)rarroverset(+5)(X)O_(3)^(-)+Cr^(3+)`
`6xx10^(-3)xx6=(5n)xx9xx10^(-3)rarrn=1`
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Knowledge Check

  • 6xx10^(-3) mole K_(2)Cr_(2) C_(7) reacts completely with 9xx10^(-3) mole X^(n+) to give XO_(3)^(-) and Cr^(3+) . The value of n is :

    A
    1
    B
    2
    C
    3
    D
    None of these

  • Number of moles of K_(2)Cr_(2)O_(7) reduced by one mole of Sn^(2+) ions is

    A
    `1/3`
    B
    3
    C
    `1/6`
    D
    6

  • Number of moles of K_(2)Cr_(2)O_(7) reduced by one mole of Sn^(2+) ions is

    A
    `1//3`
    B
    3
    C
    `1//6`
    D
    6

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    You are given a 2.198 - g sample containing a mixture of XO and X_(2)O_(3) .It requires 0.015 mol of K_(2)Cr_(2)O_(7) to oxidise the sample completely to form XO_(4)^(-) and Cr^(3+) .If 0.0817 mole XO_(4)^(-) is formed ,what is the atomic mass of X?

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