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6 xx 10^(–3) mole K(2)Cr(2)O(7) reacts c...

`6 xx 10^(–3)` mole `K_(2)Cr_(2)O_(7)` reacts completely with `9 xx 10^(–3)` mole `X^(n+)` to give `XO_(3)^(-)` and `Cr^(3+)`. Find the value of X.

Text Solution

Verified by Experts

`K_(2)Cr_(2)O_(7)+X^(n+)rarroverset(+5)(X)O_(3)^(-)+Cr^(3+)`
`6xx10^(-3)xx6=(5n)xx9xx10^(-3)rarrn=1`
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6xx10^(-3) mole K_(2)Cr_(2) C_(7) reacts completely with 9xx10^(-3) mole X^(n+) to give XO_(3)^(-) and Cr^(3+) . The value of n is :

A sample weighing 2.198 g containing a mixture of AO and A_(2)O_(3) takes 0.015 "mole of" K_(2)Cr_(2)O_(7) to oxidise the sample completely to form AO_(4)^(-) and Cr^(3+) . If 0.0187 "mole of" AO_(4)^(-) is formed, what is at.wt . of A ?

Number of moles of K_(2)Cr_(2)O_(7) can be reduced by 1 mole of Sn^(2+) ions is:

Knowledge Check

  • 6xx10^(-3) mole K_(2)Cr_(2) C_(7) reacts completely with 9xx10^(-3) mole X^(n+) to give XO_(3)^(-) and Cr^(3+) . The value of n is :

    A
    1
    B
    2
    C
    3
    D
    None of these

  • Number of moles of K_(2)Cr_(2)O_(7) reduced by one mole of Sn^(2+) ions is

    A
    `1/3`
    B
    3
    C
    `1/6`
    D
    6

  • Number of moles of K_(2)Cr_(2)O_(7) reduced by one mole of Sn^(2+) ions is

    A
    `1//3`
    B
    3
    C
    `1//6`
    D
    6