Manganese exhibits maximum oxidation state in:

Options

A. `K_(2) MnO_(4)`
B. `KMnO_(4)`
C. `MnO_(2)`
D. `Mn_(2) O_4`

Answer

To determine the maximum oxidation state of manganese from the given compounds, we will analyze each compound step by step.

### Step 1: Understand the oxidation states
Manganese (Mn) can exhibit multiple oxidation states, with +7 being the highest. We will calculate the oxidation state of manganese in each of the provided compounds.

### Step 2: Analyze K2MnO4
1. The oxidation state of potassium (K) is +1.
2. The oxidation state of oxygen (O) is -2.
3. The formula for K2MnO4 can be set up as:
\[ 2(+1) + x + 4(-2) = 0 \]
where \( x \) is the oxidation state of manganese.
4. Simplifying this:
\[ 2 + x - 8 = 0 \implies x - 6 = 0 \implies x = +6 \]
Thus, the oxidation state of manganese in K2MnO4 is +6.

### Step 3: Analyze KMnO4
1. The oxidation state of potassium (K) is +1.
2. The oxidation state of oxygen (O) is -2.
3. The formula for KMnO4 can be set up as:
\[ +1 + x + 4(-2) = 0 \]
4. Simplifying this:
\[ 1 + x - 8 = 0 \implies x - 7 = 0 \implies x = +7 \]
Thus, the oxidation state of manganese in KMnO4 is +7.

### Step 4: Analyze MnO2
1. The oxidation state of oxygen (O) is -2.
2. The formula for MnO2 can be set up as:
\[ x + 2(-2) = 0 \]
3. Simplifying this:
\[ x - 4 = 0 \implies x = +4 \]
Thus, the oxidation state of manganese in MnO2 is +4.

### Step 5: Analyze Mn2O4
1. The oxidation state of oxygen (O) is -2.
2. The formula for Mn2O4 can be set up as:
\[ 2x + 4(-2) = 0 \]
3. Simplifying this:
\[ 2x - 8 = 0 \implies 2x = 8 \implies x = +4 \]
Thus, the oxidation state of manganese in Mn2O4 is +4.

### Step 6: Conclusion
After analyzing all the compounds:
- K2MnO4: +6
- KMnO4: +7
- MnO2: +4
- Mn2O4: +4

The maximum oxidation state of manganese is found in KMnO4, which is +7.

### Final Answer:
Manganese exhibits maximum oxidation state in **KMnO4**.

---