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The string of a kite is 150 m long and i...

The string of a kite is 150 m long and it makes an angle `60^(@)` with the horizontal. Find the height of the kite above the ground. (Assume string to be tight)

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To find the height of the kite above the ground, we can use trigonometric ratios. Here’s a step-by-step solution: ### Step 1: Understand the Problem We have a kite flying at the end of a string that is 150 meters long, making an angle of 60 degrees with the horizontal. We need to find the height of the kite above the ground. ### Step 2: Draw a Diagram Draw a right triangle where: - The horizontal line represents the ground. - The hypotenuse (the string) is 150 m long. - The angle between the string and the horizontal ground is 60 degrees. - The vertical line represents the height (h) of the kite above the ground. ### Step 3: Identify the Triangle In the right triangle formed: - The hypotenuse (AC) is the length of the string = 150 m. - The angle (C) is 60 degrees. - The height (AB) is what we need to find. ### Step 4: Use the Sine Function We can use the sine function, which relates the angle to the opposite side (height) and the hypotenuse: \[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \] For our triangle: \[ \sin(60^\circ) = \frac{h}{150} \] ### Step 5: Substitute the Value of Sine The value of \(\sin(60^\circ)\) is \(\frac{\sqrt{3}}{2}\). Therefore, we can write: \[ \frac{\sqrt{3}}{2} = \frac{h}{150} \] ### Step 6: Solve for h Now, we can solve for h: \[ h = 150 \times \frac{\sqrt{3}}{2} \] \[ h = 75\sqrt{3} \text{ meters} \] ### Final Answer The height of the kite above the ground is \(75\sqrt{3}\) meters. ---
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