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Are sets A={1,2,3,4,},B={X: X in N and 5...

Are sets `A={1,2,3,4,},B={X: X in N and 5 le x le 7}` disjoint ?Justify?

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To determine if the sets \( A \) and \( B \) are disjoint, we need to analyze the elements of both sets and check if they share any common elements. ### Step-by-Step Solution: 1. **Identify the elements of Set A:** \[ A = \{1, 2, 3, 4\} \] 2. **Define Set B:** Set \( B \) is defined as: \[ B = \{ x : x \in \mathbb{N} \text{ and } 5 \leq x \leq 7 \} \] This means \( B \) includes natural numbers \( x \) that are greater than or equal to 5 and less than or equal to 7. 3. **List the elements of Set B:** The natural numbers in the range from 5 to 7 are: \[ B = \{5, 6, 7\} \] 4. **Check for common elements:** Now, we need to check if there are any common elements between sets \( A \) and \( B \). - Elements of \( A \): \( 1, 2, 3, 4 \) - Elements of \( B \): \( 5, 6, 7 \) 5. **Determine the intersection of Sets A and B:** The intersection \( A \cap B \) is the set of elements that are in both \( A \) and \( B \). Since: \[ A \cap B = \{ \} \quad (\text{no common elements}) \] 6. **Conclusion:** Since the intersection of sets \( A \) and \( B \) is empty, we conclude that the sets are disjoint. ### Final Answer: Sets \( A \) and \( B \) are disjoint because they have no elements in common. ---
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Knowledge Check

  • Let U = {x in N: 1 le x le 10} be the universal set, N being the set of natural numbers If A = {1, 2, 3, 4} and B = {2, 3, 6, 10}, then what is the complement of (A-B)?

    A
    `{6, 10}`
    B
    `{1, 4}`
    C
    `{2,3,5,6,7,8,9,10}`
    D
    `{5,6,7,8,9,10}`
  • If A={x:x in N and xlt6(1)/(4)} and B={x: x in N and x^(2)le5) the number of subsets of set Axx(AcapB) which contains exactly 3 elements is

    A
    126
    B
    280
    C
    220
    D
    144
  • If the function f(x) = {(5x-4, ",","if"0 lt x le 1),(4x^(2)+3bx, ",", "if"1 lt x le 2 ):} is continuous at every point of its domain, then the value of b is

    A
    `-1`
    B
    0
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