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If sum of first n terms of an A.P is 2n^...

If sum of first n terms of an A.P is `2n^(2)` + 7n, write its nth term.

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To find the nth term of the arithmetic progression (A.P.) given that the sum of the first n terms \( S_n \) is \( 2n^2 + 7n \), we can follow these steps: ### Step 1: Identify the formula for the nth term The nth term \( a_n \) of an A.P. can be found using the formula: \[ a_n = S_n - S_{n-1} \] where \( S_n \) is the sum of the first n terms and \( S_{n-1} \) is the sum of the first \( n-1 \) terms. ### Step 2: Calculate \( S_{n-1} \) Given \( S_n = 2n^2 + 7n \), we need to find \( S_{n-1} \). To do this, we substitute \( n-1 \) into the formula for \( S_n \): \[ S_{n-1} = 2(n-1)^2 + 7(n-1) \] ### Step 3: Simplify \( S_{n-1} \) Now, we simplify \( S_{n-1} \): \[ S_{n-1} = 2(n^2 - 2n + 1) + 7(n - 1) \] \[ = 2n^2 - 4n + 2 + 7n - 7 \] \[ = 2n^2 + 3n - 5 \] ### Step 4: Find \( a_n \) Now that we have both \( S_n \) and \( S_{n-1} \), we can find \( a_n \): \[ a_n = S_n - S_{n-1} \] \[ = (2n^2 + 7n) - (2n^2 + 3n - 5) \] \[ = 2n^2 + 7n - 2n^2 - 3n + 5 \] \[ = (7n - 3n) + 5 \] \[ = 4n + 5 \] ### Final Answer Thus, the nth term \( a_n \) of the A.P. is: \[ \boxed{4n + 5} \]
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Knowledge Check

  • If the sum of first n terms of an A.P. is 3n^(2)-2n , then its 19th term is

    A
    123
    B
    118
    C
    109
    D
    107
  • If the sum of first n terms of an A.P. is an^(2) + bn and n^(th) term is An + B then

    A
    A= 2a
    B
    A = a
    C
    a = 2A
    D
    A = 3a
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