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A physical quantity is measured as Q = (...

A physical quantity is measured as `Q = (2.1 ± 0.5)` units. Calculate the percentage error in `(1) Q^(2) (2) 2Q`.

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AI Generated Solution

To solve the problem of calculating the percentage error in \( Q^2 \) and \( 2Q \) given the measurement \( Q = (2.1 \pm 0.5) \) units, we will follow these steps: ### Step 1: Understand the given values We have: - Measured value of \( Q = 2.1 \) - Absolute error in \( Q \) (denoted as \( \Delta Q \)) = 0.5 ### Step 2: Calculate the percentage error in \( Q^2 \) ...
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Knowledge Check

  • A physical quantity x is calculated from x = ab^(2)//sqrt(c ) . Calculate the percentage error in measuring x when the percentage errors in measuring a , b , and c are 4 , 2 , and 3%, respectively .

    A
    `7%`
    B
    `9%`
    C
    `11%`
    D
    `9.5%`

  • Let x={:[(a^(2)b^(2))/(c)]:} be the physical quantity. If the percentage error in the measurement of physical quantities a,b, and c is 2,3 and 4 per cent respectively, then percentage error in the measurement of x is

    A
    `7%`
    B
    `14%`
    C
    `21%`
    D
    `28%`

  • In an experiment , the percentage of error occurred in the measurement of physical quantities A,B,C and D are 1% , 2% , 3% and 4% respectively. Then the maximum percentage of error in the measurement of X, where X = (A^2 B^(1//2))/(C^(1//3 D^3) will be

    A
    `(3/13)%`
    B
    `16%`
    C
    `-10%`
    D
    `10%`

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