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If momentum (p), area (A) and time(t) ar...

If momentum `(p)`, area `(A)` and time`(t) `are taken to be fundamental quantities then energy has the dimensional formula

A

`[pA^(1//2)T^(-1)]`

B

`[pA^(-1//2)T^(1)]`

C

`[p^(2)AT]`

D

`[pA^(-1)T]`

Text Solution

Verified by Experts

The correct Answer is:
A
Energy = Force `×` Length
`=("change in momentum")/("time")xxsqrt("area")=[pA^(1//2)A^(-1)]`
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