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If momentum (p), area (A) and time(t) ar...

If momentum `(p)`, area `(A)` and time`(t) `are taken to be fundamental quantities then energy has the dimensional formula

A

`[pA^(1//2)T^(-1)]`

B

`[pA^(-1//2)T^(1)]`

C

`[p^(2)AT]`

D

`[pA^(-1)T]`

Text Solution

Verified by Experts

The correct Answer is:
A

Energy = Force `×` Length
`=("change in momentum")/("time")xxsqrt("area")=[pA^(1//2)A^(-1)]`
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Knowledge Check

  • If momentum (P) , area (A) and time (7) are taken to be fundamental quntities, then power has the dimensional formula.

    A
    `(P^(1)A^(-1)T^(1))`
    B
    `(P^(2)A^(1)T^(1))`
    C
    `(P^(1)A^(-1//2)T^(1))`
    D
    `(P^(1)A^(1//2)T^(-2))`
  • If momentum P, area A and time T are selected as fundamental quantities then energy has the dimensional formula

    A
    `[P^(2)A^(2)T^(-1)]`
    B
    `[P^(-1)A^(-1//2)T^(1)]`
    C
    `[P^(1)A^(1//2)T^(-1)]`
    D
    `[P^(-2)A^(-2)T^(1)]`
  • If momentum (P), area (A) and time (T) are assumed to be formula :

    A
    `[PTA^(-1//2)]`
    B
    `[PT^(-1) A^(1//2)]`
    C
    `[P^(2)T^(-1)A]`
    D
    `[PTA^(-1)]`
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