Find the force required to move a train of 2000 quintals up an incline of 1 in 50 , with an acceleration of `2 ms^(-2)` , the force of friction being 0.5 newton per quintal .

Explanation

Force of friction =0.5N per qunital
`f=0.5 xx 2000=1000N`
`m=2000" quintals"=2000 xx 100 kg`
`sin theta=1/50, a=2m//s^(2)`
In moving up an inclined plane, force required against gravity
`=mg sin theta= 39200N`
And force required to produce acceleration `=ma = 2000 xx 100 xx 2= 40,0000 N`
Total force required =1000 + 39,200 + 40,0000
`=440200 N.`