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A proton and an a-particle have the same...

A proton and an a-particle have the same de-Broglie wavelength. Determine the ratio of
their accelerating potentials

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To solve the problem of determining the ratio of the accelerating potentials of a proton and an alpha particle that have the same de-Broglie wavelength, we can follow these steps: ### Step 1: Understand the de-Broglie wavelength formula The de-Broglie wavelength (\( \lambda \)) of a particle is given by the formula: \[ \lambda = \frac{h}{p} \] where \( h \) is Planck's constant and \( p \) is the momentum of the particle. ...
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A proton and an a-particle have the same de-Broglie wavelength. Determine the ratio of their speeds.

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Knowledge Check

  • If a proton and electron have the same de Broglie wavelength, then

    A
    kinetic energy of electron `lt` kinetic energy of proton
    B
    kinetic energy of electron = kinetic energy of proton
    C
    momentum of electron = momentum of proton
    D
    momentum of electron `lt` momentum of proton
  • Protons and alpha -particles have the same de Broglie wavelength. What is same for both of them?

    A
    mass
    B
    linear momentum
    C
    frequency
    D
    energy
  • An electron and proton have the same de-Broglie wavelength. Then the kinetic energy of the electron is

    A
    Zero
    B
    Infinity
    C
    Equal to the kinetic energy of the proton
    D
    Greater than the kinetic energy of the proton
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    (i) Show that the de-Broglie's wavelength of electrons accelerated through a potential V volts can be expressed as lamda=(h)/(sqrt(meV)) . What is the de-Broglie wavelength of a 2kg object moving with a speed of 1ms^(-1) ? (ii) Calculate the ratio of the accelerating potential required to accelerate (i) a proton and (ii) an alpha particle to have the same de-Broglie wavelength associated with them. [Given: mass of proton =1.6xx10^(-27)kg . Mass of alpha -particle= 6.4xx10^(-27)kg ].

    Find the ratio of velocities of proton and alpha -particle if the de Broglie wavelengths of both the particles is same.

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