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If a tower subtends equal angles at four...

If a tower subtends equal angles at four points P, Q , R and S that lie in a plane containing the foot of the tower , the which fo the following statements is always true (here, the tower is perpendicular to the plane containing the points P, Q,R,S)

A

`anglePQS=anglePRS`

B

`anglePQR+anglePSR=180^@`

C

`anglePQS=90^@rArranglePRS=90^@`

D

`(PQ)(RS)+(PS)(RQ)=(PR)(QS)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the situation where a tower subtends equal angles at four points P, Q, R, and S that lie in a plane containing the foot of the tower. The tower is perpendicular to this plane. ### Step-by-Step Solution: 1. **Understanding the Geometry**: - Let the foot of the tower be point O and the top of the tower be point B. The height of the tower is denoted as \( h \). - The points P, Q, R, and S are located in the horizontal plane at distances from point O. 2. **Equal Angles Subtended**: - Since the tower subtends equal angles at points P, Q, R, and S, we denote this angle as \( \theta \). Thus, we have: \[ \angle POB = \angle QOB = \angle ROB = \angle SOB = \theta \] 3. **Using Trigonometry**: - From the definition of tangent in a right triangle, we can express the distances OP, OQ, OR, and OS in terms of \( h \) and \( \theta \): \[ OP = h \tan(\theta), \quad OQ = h \tan(\theta), \quad OR = h \tan(\theta), \quad OS = h \tan(\theta) \] - This indicates that all points P, Q, R, and S are equidistant from point O. 4. **Cyclic Quadrilateral**: - Since all four points are equidistant from O, they lie on a circle centered at O. Therefore, quadrilateral PQRS is a cyclic quadrilateral. - A property of cyclic quadrilaterals is that the sum of the opposite angles is equal to 180 degrees: \[ \angle PQR + \angle PSR = 180^\circ \quad \text{and} \quad \angle PQS + \angle PRS = 180^\circ \] 5. **Analyzing the Options**: - **Option 1**: \( \angle PQS = \angle PRS \) - This is not necessarily true. - **Option 2**: \( \angle PQR + \angle PSR = 180^\circ \) - This is true for cyclic quadrilaterals, but it may not always hold depending on the order of points. - **Option 3**: \( \angle PQS = 90^\circ \) implies \( \angle PRS = 90^\circ \) - This is true because both angles subtend the same chord PS. - **Option 4**: The statement about products of sides and diagonals is not always true. 6. **Conclusion**: - The only statement that is always true is **Option 3**: \( \angle PQS = 90^\circ \) implies \( \angle PRS = 90^\circ \). ### Final Answer: The correct statement that is always true is: **Option 3: \( \angle PQS = 90^\circ \) implies \( \angle PRS = 90^\circ \)**.
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Knowledge Check

  • A tower subtends an angle alpha at a point A in the plane of its base and the angle of depression of the foot of the tower at a point l m just above A is beta . The height of the tower is

    A
    `l tan beta cot alpha`
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    `l tan alpha cot beta`
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    A
    `b tan alpha.tanbeta`
    B
    `b(cot beta)/(cot alpha)`
    C
    `b(tan beta)/(tan alpha).sinalpha`
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