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The table below gives the results of thr...

The table below gives the results of three titrations carried out with 0.200 M HCl to determine the molarity of a given NaOH solution using phenolphthalein as indicator. NaOH was taken in the burette and HCl was taken in a conical flask for the titrations

The actual molarity of the prepared NaOH solution was `"0.220 mol dm"^(-3)`. Which among the following could be the reason for the wrong value obtained in titration III?

A

Number of drops of phenolphthalein added to the titration flask was more in this titration

B

The concentration of HCl was wrongly used as 0.250 M for the calculation of M NaOH

C

A few drops of NaOH solution were spilled outside the titration flask during titration

D

A few drops of the neutralized solution from titration II were left behind in the flask

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The table below shows the data for three titrations to determine the concentration of a NaOH solution With standard 0.200 M HCl solution using phenolphthalein as the indicator Which explanation best accounts for the lower value of the NaOH M in Trial 3 ?

    A
    Some of the neutralized solution from Trial 2 was left in the flask for Trial 3.
    B
    The numner of drops of phenolphtalein was doubled in Trial 3.
    C
    The HCl concentration was used as 0.250 M in the NaOH molarity calculation .
    D
    A few drops of NaOH solution were spilled on the desktop in Trial 3.

  • 2.5 litres of 1M NaOH solution is mixed with 3.0 litres of 0.5 M NaOH solution. The molarity of resulting solution is :

    A
    0.80 M
    B
    1.0 M
    C
    0.73 M
    D
    0.50 M

  • 2.5 litre of 1M NaOH solution is mixed with a 3.0 litres of 0.5 M NaOH solution. The molarity of the resulting solution is :

    A
    0.80 M
    B
    1.0 M
    C
    0.73 M
    D
    0.50 M.
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