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The radial wave equation for hydrogen of...

The radial wave equation for hydrogen of radial nodes from nucleus are:
`Psi_(1s)=(1)/(16sqrt(4))(1/a_(0))^(3//2) [("x"-1)("x"^(2)-8"x"+12)]e^(-x//2)`
where, `x=2r//a_(0),a_(0)` = radius of first Bohr orbit
The minimum and maximum position of radial nodes from nucleus are:

A

`a_(o), 3a_(o)`

B

`0.5a_(o), 3a_(o)`

C

`0.5a_(o), a_(o)`

D

`0.5a_(o), 4a_(o)`

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The correct Answer is:
B
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The radial wave equyation for hydrogen of radial nodes from nucleus are: Psi_(1s)=(1)/(16sqrt(4))(1/a_(0))^(3//2) [("x"-1)("x"^(2)-8"x"+12)]e^(-x//2) where, x=2r//a_(0),a_(0) = radius of first Bohar orbit The minimum and maximum position of radial nodes from nucles are:

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For H-atom wave function for a particulaonstate is: Psi=(1)/(81sqrt(3pi))((1)/(a_(0)))^(3//2) (sigma^(2)-10sigma+25)e Where sigma=r//a_(0) and a_(0) is Bohr's radius (0.53overset(@)A) . Then distance of farthest radius mode is approximately.

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