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The number of molecules with pyramidal s...

The number of molecules with pyramidal shape are :
`NH_(3), ClF_(3), SO_(3), PCl_(3), XeO_(3), BCl_(3), ClO_(3)^(-), SO_(3)^(2-)`

A

5

B

4

C

3

D

6

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of molecules with a pyramidal shape among the given options, we need to analyze the hybridization and the arrangement of bond pairs and lone pairs for each molecule. A pyramidal shape typically arises when there are three bond pairs and one lone pair (sp³ hybridization). ### Step-by-Step Solution: 1. **NH₃ (Ammonia)**: - Nitrogen (N) has 5 valence electrons. - It forms 3 bonds with hydrogen (H) and has 1 lone pair. - Steric number = 3 (bond pairs) + 1 (lone pair) = 4. - Hybridization: sp³. - Shape: Pyramidal. - **Conclusion**: NH₃ has a pyramidal shape. 2. **ClF₃ (Chlorine trifluoride)**: - Chlorine (Cl) has 7 valence electrons. - It forms 3 bonds with fluorine (F) and has 2 lone pairs. - Steric number = 3 (bond pairs) + 2 (lone pairs) = 5. - Hybridization: sp³d. - Shape: T-shaped, not pyramidal. - **Conclusion**: ClF₃ does not have a pyramidal shape. 3. **SO₃ (Sulfur trioxide)**: - Sulfur (S) has 6 valence electrons. - It forms 3 double bonds with oxygen (O). - Steric number = 3 (bond pairs) + 0 (lone pairs) = 3. - Hybridization: sp². - Shape: Trigonal planar, not pyramidal. - **Conclusion**: SO₃ does not have a pyramidal shape. 4. **PCl₃ (Phosphorus trichloride)**: - Phosphorus (P) has 5 valence electrons. - It forms 3 bonds with chlorine (Cl) and has 1 lone pair. - Steric number = 3 (bond pairs) + 1 (lone pair) = 4. - Hybridization: sp³. - Shape: Pyramidal. - **Conclusion**: PCl₃ has a pyramidal shape. 5. **XeO₃ (Xenon trioxide)**: - Xenon (Xe) has 8 valence electrons. - It forms 3 bonds with oxygen (O) and has 1 lone pair. - Steric number = 3 (bond pairs) + 1 (lone pair) = 4. - Hybridization: sp³. - Shape: Pyramidal. - **Conclusion**: XeO₃ has a pyramidal shape. 6. **BCl₃ (Boron trichloride)**: - Boron (B) has 3 valence electrons. - It forms 3 bonds with chlorine (Cl) and has 0 lone pairs. - Steric number = 3 (bond pairs) + 0 (lone pairs) = 3. - Hybridization: sp². - Shape: Trigonal planar, not pyramidal. - **Conclusion**: BCl₃ does not have a pyramidal shape. 7. **ClO₃⁻ (Chlorate ion)**: - Chlorine (Cl) has 7 valence electrons. - It forms 3 bonds with oxygen (O) and has 1 lone pair. - Steric number = 3 (bond pairs) + 1 (lone pair) = 4. - Hybridization: sp³. - Shape: Pyramidal. - **Conclusion**: ClO₃⁻ has a pyramidal shape. 8. **SO₃²⁻ (Sulfite ion)**: - Sulfur (S) has 6 valence electrons. - It forms 3 bonds with oxygen (O) and has 1 lone pair. - Steric number = 3 (bond pairs) + 1 (lone pair) = 4. - Hybridization: sp³. - Shape: Pyramidal. - **Conclusion**: SO₃²⁻ has a pyramidal shape. ### Final Count of Pyramidal Molecules: - The molecules with a pyramidal shape are: **NH₃, PCl₃, XeO₃, ClO₃⁻, and SO₃²⁻**. - Total: **5 molecules**.
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