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A chain is placed on a rough table, part...

A chain is placed on a rough table, partially hanging, as shown in the figure. The coefficient of static friction between the chain and the table is `mu` = 0.4. If the maximum possible length of the hanging part is x and the length of the chain is L, then what is the value of `(L)/(x)`?

Text Solution

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The correct Answer is:
3.8
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Knowledge Check

  • A uniform chain of length L is resting on a table with a part of its hanging over the edge . If the coefficient of static friction between the chain and the table is mu , the maximum length of the hanging part is

    A
    ` (muL)/(1+mu)`
    B
    `(muL)/(1-mu)`
    C
    ` ((1-mu)L)/(1+mu)`
    D
    `muL`

  • A homogoneous chain of length L lies on a table. The coefficient of friction between the chain and the table is mu . The maximum length which can hang over the table in equilibrium is

    A
    `((mu)/(mu+1))L`
    B
    `((1-mu)/(mu))L`
    C
    `((1-mu)/(1+mu))L`
    D
    `((2mu)/(2mu+1))L`

  • A heavy uniform chain lies on horizontal table top. If the coefficient of friction between the chain and the table surface is 0.5, the maximum percentage of the length of the chain that can hang over one edge of the table is

    A
    `20%`
    B
    `33.3%`
    C
    `76%`
    D
    `50%`

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    A heavy uniform chain lies on horizontal table top. If the coefficient of friction between the chain and the table surface is 0.25, the maximum percentage of the length of the chain that can hang over one edge of the table is

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    A uniform chain of mass m and length I is kept on the table with a part of it overhanging (see figure). If the coefficient of friction between the table and the chain is 1//3 then find the maximum length of the chain that can overhang such that the chain remain in equilibrium.

    A uniform chain is placed at rest on a rought surface of base length 1 and height h on an irregular suface as shown in figure Then the minimum coefficient of friction between the chain and the surface must be equal to

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