The electronic configuration of few elements is given below. Mark the statement which is not correct about these elements.
(i) `1s^(2)2s^(2)2p^(6)3s^(1)`
(ii) `1s^(2)2s^(2)2p^(5)`
(iii) `1s^(2)2s^(2)2p^(6)`
(iv) `1s^(2)2s^(2)2p^(3)`

Options

A. (i) is an alkali metal
B. (iii) is a noble metal
C. (i) and (ii) form ionic compound
D. (iv) has high ionisation enthalpy than accepted

Answer

To determine which statement is not correct about the given electronic configurations, we will analyze each configuration step by step.

1. **Identify the Elements**:
- (i) `1s² 2s² 2p⁶ 3s¹`: This configuration corresponds to Sodium (Na), which is in Group 1 (alkali metals).
- (ii) `1s² 2s² 2p⁵`: This configuration corresponds to Fluorine (F), which is in Group 17 (halogens).
- (iii) `1s² 2s² 2p⁶`: This configuration corresponds to Neon (Ne), which is a noble gas in Group 18.
- (iv) `1s² 2s² 2p³`: This configuration corresponds to Nitrogen (N), which is in Group 15 (p-block elements).

2. **Analyze the Statements**:
- **Statement (i)**: Sodium is an alkali metal. This statement is correct.
- **Statement (ii)**: Fluorine is a halogen. This statement is correct.
- **Statement (iii)**: Neon is a noble gas. This statement is correct.
- **Statement (iv)**: Nitrogen is a p-block element but is not a noble gas. This statement is correct.

3. **Identify the Incorrect Statement**:
- The question asks for the statement that is not correct. The only potential confusion arises from the terminology used in the video transcript. The mention of "noble metal" in relation to Neon is incorrect, as Neon is a noble gas, not a noble metal.

4. **Conclusion**:
- The statement that is not correct is the one that refers to Neon as a "noble metal" instead of a "noble gas."

**Final Answer**: The statement referring to Neon as a "noble metal" is not correct.

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